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maxonik [38]
2 years ago
11

Pleaseeeeeee I need HELP in 20 mins,Asap!!!

Physics
1 answer:
Juliette [100K]2 years ago
3 0

The velocity of the third piece is 124.02 m/s at 1.05⁰ below the horizontal.

<h3>Velocity of the third piece</h3>

The velocity of the third piece is calculated from the principle of conservation of linear momentum.

mu = m₁u₁ + m₂u₂ + m₃u₃

where;

  • m is mass of the clay
  • u is velocity of the clay
  • u₁ is velocity of first piece
  • u₂ is velocity of second piece
  • u₃ is velocity of third piece
  • m₃ is mass of the third piece = 6 kg - (2 kg + 1 kg) = 3 kg
<h3>Momentum in y - direction</h3>

6(22)sin(0) = 2(10)sin32 - 1(8)sin(28) + 3u₃y

0 = 6.84 + 3u₃y

u₃y = -6.84/3

u₃y = -2.28 m/s

<h3>Change in momentum</h3>

ΔP = Pf - Pi = J

where;

  • Pf is final momentum
  • Pi is the initial momentum
  • J is impulse

2640(0.1) = 2(10)cos32 +  1(8)cos(28) + 3u₃x - 6(22)

264 = -108 + 3u₃x

3u₃x = 372

u₃x = 372/3

u₃x = 124 m/s

<h3>Resultant velocity</h3>

u₃ = √(124² + 2.28²)

u₃ = 124.02 m/s

<h3>Direction of the velocity</h3>

tanθ = u₃y/u₃x

tanθ = 2.28/124

tanθ = 0.018

θ = 1.05⁰ (below the horizontal)

Learn more about linear momentum here: brainly.com/question/7538238

#SPJ1

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