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3 years ago

Which contributions did Johannes Kepler make? Check all that apply.

Physics

2 answers:

gayaneshka [121]3 years ago

7 0

Answer:

Its 4,5,

Explanation:

Leto [7]3 years ago

5 0

Answer:

the answers are 2, 4, and 5.

Explanation:

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A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 70

JulijaS [17]

Answer:

a = 580 m/s^2

Explanation:

Given:

- Distance for accelerated throw s_a = 70 cm

- Angle of throw Q = 30 degrees

- Distance traveled by the javelin in horizontal direction x(f) = 75 m

- Initial height of throw y(0) = 0

- Final height of the javelin y(f) = -2 m

Find:

What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

Solution:

- Compute initial components of the velocity:

V_x,i = V*cos(30)

V_y,i = V*sin(30)

- Use second equation of motion in horizontal direction:

x(f) = x(0) + V*cos(30)*t

75 = 0 + V*cos(30)*t

t = 75 /V*cos(30)

- Use equation of motion in vertical direction:

y(f) = y(0) + V_y,i*t + 0.5*g*t^2

Subs the values:

-2 = 0 + V*sin(30)*75/V*cos(30) - 4.905*(75/Vcos(30))^2

-2 = 75*tan(30) - 4.905*(5625/V^2*cos^2(30))

V^2 = 4.905*5625 / (2 + 75*tan(30))*cos^2(30)

V^2 = 812.0633

V = 28.5 m/s

- Use the third equation of motion in the interval of the throw:

V^2 = U^2 + 2*a*s_a

28.5^2 = 2*a*0.7

a = 580 m/s^2

6 0

3 years ago

How many phase conductors are installed between the switch and the light fixture shown in the figure? A. Four

BARSIC [14]

Answer:

TWO

Explanation:

3 0

3 years ago

A kangaroo jumps up with an initial velocity of 36 feet persecond from the ground (assume its starting height is 0 feet).Use the

kkurt [141]

Given

Initial velocity:

36 ft/s

Initial height:

0 ft

Vertical motion model:

h(t) = -16t^2 + ut + s

v = initial velocity

s = is the height

Procedure

We are going to use the model provided for the vertical motion.

$\begin{gathered} h(t)=-16t^2+36t+0 \\ h(t)=-16t^2+36t \end{gathered}$

We know that at the maximum height the final velocity is 0.

Then we will use the following expression to calculate the maximum height:

$\begin{gathered} v^2_f=v^2_o-2ah_{\max } \\ 0=v^2_o-2ah_{\max } \\ 2ah_{\max }=v^2_o \\ h_{\max }=\frac{v^2_o}{2a} \\ h_{\max }=\frac{(36ft/s)^2}{2\cdot32ft/s^2} \\ h_{\max }=20.25\text{ ft} \end{gathered}$

Now for time:

$\begin{gathered} 20.25=-16t^2+36t \\ 16t^2-36t+20.25=0 \end{gathered}$

Solving for t,

$\begin{gathered} t_1=2.25 \\ t_2=0 \end{gathered}$

The total time the kangaroo takes in the air is 2.3s.

3 0

1 year ago

Will give brainlist!! Please help!!

kupik [55]

Answer:

microwave, visible light, and radio waves.

Explanation:

6 0

3 years ago

Physics multiple choice

Aleksandr-060686 [28]

10. b

11.d

12. b

13.e

I hope this helps

3 0

4 years ago

Read 2 more answers