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3 years ago

How is a full moon different from a new moon?

Physics

2 answers:

koban [17]3 years ago

8 0

<span>A full moon is at its brightest, and here is no disk to be seen. New moons are barely visable.</span>

joja [24]3 years ago

8 0

Answer:

During the full moon phase, the entire illuminated portion of the moon is visible from Earth. This occurs when the Earth comes between the sun and the moon. We see a bright disc of the moon.

On the other hand, during new moon phase, the entire illuminated portion of the moon faces away from the earth and we don't see the lit face of the moon. This happens when the moon comes between the Sun and the Earth. Viewing a new moon is very difficult as the moon appears very dark.

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A force platform is a tool used to analyze the performance of athletes measuring the vertical force that the athlete exerts on t

Phoenix [80]

Answer:

a. $I=981.34 N*s$

b. $v_f=3.96 m/s$

c. $v_{f1}=3.63m/s$

d. $y_f=0.673m$

Explanation:

Given: $m=67kg$ , $h=0.720m$ , $0$

$I=\int\limits^{t_1}_{t_2} {F(t)} \, dt$

$F(t)=9200*t-11500t^2$

$I=\int\limits^{0.8s}_{0s}{9200*t-11500*t^2} \, dt$

$I=4600*t^2-3833.3*t^3|(0.80,0)$

$I=2944-1962.66=981.35$

$I=981.34 N*s$

$v_f^2=v_i^2+a*y'$

Starting from the rest

$v_f^2=0+2*9.8m/s^2*0.80s$

$v_f^2=15.68$

$v_f=\sqrt{15.68m^2/s^2}=3.96 m/s$

$I_{total}=p_f$

$I_1-m*g*d=m*v_{f1}-m*v_f$

$981.34-67kg*9.8m/s^2*0.720=67.0kg*v_{f1}-67.0kg*(-3.96m/s)$

Solve to vf

$v_{f1}=3.63m/s$

$v_f^2=v_i^2+2*a*y_f'$

$y_f'=v_i/2*a =(3.63m/s)^2/2*9.8m/s^2$

$y_f=0.673m$

7 0

3 years ago

Which of the following statements does NOT use the term angular size or angular distance correctly?

Verizon [17]

Answer: Statement 1 is incorrect.

Reason:

Unit of measure of angular distance is not meters.

Explanation:

The term 'angular size' is used to describe the apparent size of the objects in the night sky.

The angular distance is defined as the angle through which an object moves on a circular path. The SI unit is radian.

Other units are revolution (rev) and degrees.

In statement 1, angular distance is measured in meters which is incorrect. In other options, there is no factual mistake so they are correct.

Let's discuss them,

Statement 2:

Here, we are talking about the use of outstretched hand to estimate the angular distances and sizes which is correct.

Statement 3:

This statement talks about the same angular sizes of the sun and the moon, here the term is again used correctly.

Statement 4:

Here, the angular distance is measured in the correct units i.e, degrees so this statement is also correct.

3 0

3 years ago

What is the ultimate source of energy for all living things

miskamm [114]

The sun . plz give me a nice thank you

3 0

3 years ago

If your runnin at full speed for an average human, and lept over a 10 foot brook would you make it?

Vika [28.1K]

Unless you are a mutant....I don't think you would make it. I'm 5'8" and most people are 6'7" or less. It's bsically impossible to do. :)

7 0

3 years ago

Read 2 more answers

Which of acceleration, age, speed, temperature, and velocity are vector quantities?.

ollegr [7]

Velocity and acceleration are vector quantities whereas speed, temperature and age are not.

<h3>What is a vector quantity?</h3>

Vector is a quantity that has both magnitude and direction and is represented by an arrow whose direction is same as that of the quantity and length is proportional to the quantity's magnitude.

Vector has magnitude and direction but it does not have position. Velocity and acceleration both are vector quantities as they have magnitude and direction.

If the speed of an object remains same but direction changes then the object is accelerating. It is important to remember that acceleration and velocity aren't always in the same direction.

To know more about vector quantity, refer

brainly.com/question/626479

#SPJ1

4 0

1 year ago