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GREYUIT [131]
2 years ago
15

Which article of the NEC describes the proper placement of outlets in this type of room? Also, based on the given load what type

of outlets are needed for this room?
Engineering
1 answer:
zmey [24]2 years ago
7 0

The Article of the NEC that describes the proper placement of outlets in rooms is the Article 210.

<h3>What is NEC?</h3>

NEC is the short or acronym for National Electric Code.

For example, with regard to Receptacles, section (210-21(b)) of the Article 100 indicates that a "Receptacle" is a contact device provided at an outlet for the connecting of an attachment plug.

The terms "receptacle" and "receptacles" occur often in the National Electrical Code (NEC).

Learn more about NEC at;
brainly.com/question/14507799
#SPJ1

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Discuss four (4) advantages of direct and indirect water supply system.
Reil [10]

Answer and Explanation:

Some of the advantages of direct water supply system are:

  • Smaller size of the cistern
  • No risk of polluted water
  • Ease of installation
  • Lower pipe work

Some of the advantages of indirect water supply system are:

  • It can be pumped completely
  • Lower demand on the main source
  • Minimization of wear and tear on taps
  • Larger size of the cistern.
7 0
3 years ago
Read 2 more answers
A roller-coaster car is traveling at a speed of 23 m/s when it passes through point B. At that point, it enters a concave down c
ycow [4]

Answer:

See it in the pic

Explanation:

See it in the pic

8 0
3 years ago
The atomic radii of a divalent cation and a monovalent anion are 0.77 nm and 0.136 nm, respectively.1- Calculate the force of at
MrMuchimi

Answer:

A) attractive force between ions = 5.09x10^-19 N of attractive force

B) there will be no repulsion since both ions have opposite charges.

Explanation:

Detailed explanation and calculation is shown in the image below.

5 0
4 years ago
Hello, how are you? ​
Kisachek [45]

Answer:

Hello, I'm good. Thank you for asking

8 0
2 years ago
Read 2 more answers
Consider a single bacterial cell as a discrete particle with a diameter of 1x10-6m and a specific gravity of 1.01. Assuming lami
Alinara [238K]

Answer:

Sedimentation is not a good method.

Explanation:

We need to apply Stoke laws and assume that is valid here.

So,

V_s= 418(G-1)d^2(\frac{3T+70}{100})

Replacing the values,

V_s= (418)(1.01-1)(10^-3)^3*(\frac{3*20+70}{100})\\V_s=5.434*10^-6mm/s

Here then we calculate the time,

t_{req}=\frac{x}{v}

Where x= Distance, v= velocity

t_{req}=\frac{1foot}{5.434*10^{-6}} = \frac{304.8}{5.434*10^{-6}}\\t_{req}=649.2days

To calculate the surface required we need first to calculate the volume through the volume,

So,

Q=4MGD=4*10^6*0.135 (ft^3/day)

Then,

V_{req} = Q*t\\V_{req}=4*10^6*0.134*649.2\\V_{req}=34.79*10^7ft^3

Here we can calculate the surface

S_{req}= \frac{Volume}{Distance}=\frac{34.79*10^7}{1}\\S_{req}=7987.8 Acres

<em>So, the requeriment of Area of tank and settlement time is huge, it's not a practical method.</em>

6 0
3 years ago
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