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tatuchka [14]
3 years ago
7

Calculate the maximum load that a 7075 series aluminum alloy bar (with a T6 temper heat treatment) can support without permanent

ly deforming. The bar has a square cross section whose edge length is 8.1 mm.
Engineering
1 answer:
Aleksandr [31]3 years ago
6 0

Answer:

The maximum load the bar can withstand = 35.43 KN

Explanation:

Ultimate tensile strength of the given aluminium bar \sigma = 540 M pa

Cross section area of the bar = 8.1^{2}  = 65.61 mm^{2}

We know that the ultimate strength of the bar is calculated from

\sigma = \frac{P_{max} }{A}

540 = \frac{P_{max} }{65.61}

P_{max} = 540 × 65.61

P_{max} =  35.43 KN

Therefore the maximum load the bar can withstand = 35.43 KN

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A heat recovery system​ (HRS) is used to conserve heat from the surroundings and supply it to the Mars Rover. The HRS fluid loop
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Answer:

0.304 L of Freon is needed

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2 years ago
A structural component in the shape of a flat plate 25.0 mm thick is to be fabricated from a metal alloy for which the yield str
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Answer:

The critical length of surface flaw = 6.176 mm

Explanation:

Given data-

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Dimensionless parameter. Y = 1.3

The critical length of surface flaw is given by

= 1/pi.(Plane strain fracture toughness /Dimensionless parameter× Design Stress)^2

Now putting values in above equation we get,

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A dielectric material, such as Teflon®, is placed between the plates of a parallel-plate capacitor without altering the structur
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Answer: The electric field decreases because of the insertion of the Teflon.

Explanation:

If the charge on the capacitor is held fixed, the electric field as a consequence of this charge distribution (directed from the positive charged plate to the negative charged one remains unchanged.

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