Answer:
The NaOH solution has a molarity of 0.052 M
Explanation:
<u>Step 1:</u> Data given
Mass of KHP = 0.4798 grams
Volume of NaOH= 45.22 mL = 0.04522 L
Molar mass of NaOH = 40 g/mol
Molar mass of KHP = 204.22 g/mol
<u>Step 2</u>: Calculate moles of KHP
Moles KHP = mass KHP / Molar mass KHP
Moles KHP = 0.4798 grams / 204.22 g/mol
Moles KHP = 0.00235 moles
<u>Step 3</u>: Calculate moles of NaOH
KHP here acts as a mono-acid so, the number of moles of NaOH = number of moles KHP = 0.00235 moles
<u>Step 4: </u>Calculate molarity of NaOH
Molarity NaOH = moles NaOH / volume NaOH
Molarity NaOH = 0.00235 moles / 0.04522 L
Molarity NaOH = 0.052 M
The NaOH solution has a molarity of 0.052 M
