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ahrayia [7]
3 years ago
15

What element from the "Periodic Table" is named after an "Austrian Scientist"??

Chemistry
1 answer:
soldier1979 [14.2K]3 years ago
3 0

Answer:

Should be either mendele or fermium

maybe lawrencium not sure but I think it’s lawrencium! Sorry if wrong heh

Explanation: <u><em>really trying to help! If it’s wrong super sorry!!!</em></u>

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Which best explains how a single-celled organism can survive without other cells?
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They are able to perform all necessary functions within one cell.

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When pollution or harmful substances get into an environment what is it called
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Every ribosome has three tRNA binding sites: the A site, the P site, and the E site. For the given sentences, select the correct
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A 125.0 mg sample of an unknown, monoprotic acid was dissolved in 100.0 mL of distilled water and titrated with a 0.050 M soluti
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6 0
4 years ago
For each of the following unbalanced equations, calculate how many grams of each product would be produced by complete reaction
LUCKY_DIMON [66]

Answer:

The answer to your question is

Explanation:

Data

12.5 g of reactant

Balanced Reaction 1

                 TiBr₄ + 2H₂  ⇒  Ti  +  4HBr

Molar mass of TiBr₄ = 48 + (4 x 80) = 368 g

Atomic mass of Ti = 48 g

Molar mass of HBr = 1 + 80 = 81

                 368 g of TiBr₄ ---------------- 48 g of Ti

                    12.5 g of TiBr₄ -------------- x

                    x = (12.5 x 48) / 368

                   x = 1.63 g of Ti

                  368 g of TiBr₄ ----------------4(81) g of HBr

                    12.5 g of TiBr₄ -------------  x

                    x = (12.5 x 324) / 368

                    x = 11 g of HBr

Balanced reaction 2

                  3SiH₄  +  4NH₃  ⇒   Si₃N₄  +  12H₂

Molar mass of SiH₄ = 28 + 4 = 32

Molar mass of Si₃N₄ = 28 x 3 + 14 x 4 = 84 + 56 = 140 g

Atomic mass of H₂ = 2 g

                  3(32) g of SiH₄ --------------- 140 g of Si₃N₄

                    12.5 g of SiH₄ --------------  x

                    x = 18.2 g of Si₃N₄

                  3(32) g of SiH₄ --------------- 24 g of H₂

                  12.5 g of SiH₄   --------------  x

                   x = 3.125 g of H₂

5 0
4 years ago
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