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boyakko [2]
2 years ago
14

calculate the average atomic mass of lead based on the given data and the atomic masses. isotope atomic mass (amu) percent abund

ance pb-206 205.97 14.5 pb-207 206.98 17.0 pb-208 207.98 68.5
Chemistry
1 answer:
BaLLatris [955]2 years ago
8 0

The average atomic mass of lead given its three isotopes is 207.52.

<h3>What is average atomic mass?</h3>

Average atomic mass is the weighted average of the atomic masses of the naturally occurring isotopes of an element.

According to this question, the following isotopes with their percent abundance and atomic masses of lead are given:

  • Pb-206 - 205.97 14.5%
  • Pb-207 - 206.98 17.0%
  • Pb-208 - 207.98 68.5%

  • Pb-206 = 14.5/100 × 205.97
  • Pb-207 = 17/100 × 206.98
  • Pb-208 = 68.5/100 × 207.98

  • Pb-206 = 29.865
  • Pb-207 = 35.186
  • Pb-208 = 142.466

The average atomic mass is as follows: 29.865 + 35.186 + 142.466 = 207.52

Therefore, the average atomic mass of lead given its three isotopes is 207.52.

Learn more about average atomic mass at: brainly.com/question/13753702

#SPJ1

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To get the value of ΔG we need to get first the value of ΔG°:

when ΔG° = - R*T*㏑K

when R is constant in KJ = 0.00831 KJ

T is the temperature in Kelvin = 25+273 = 298 K

and K is the equilibrium constant = 4.5 x 10^-4

so by substitution:

∴ ΔG° = - 0.00831 * 298 K * ㏑4.5 x 10^-4

        = -19 KJ

then, we can now get the value of ΔG when:

ΔG = ΔG° - RT*㏑[HNO2]/[H+][NO2]

when ΔG° = -19 KJ

and R is constant in KJ = 0.00831 

and T is the temperature in Kelvin = 298 K

and [HNO2] = 0.21 m & [H+] = 5.9 x 10^-2 & [NO2-] = 6.3 x 10^-4 m  

so, by substitution:

ΔG = -19 KJ - 0.00831 * 298K* ㏑(0.21/5.9x10^-2*6.3 x10^-4 )

       = -40

     
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