This is because iron is more reactive than copper in the metal reactivity series.
The metal reactivity series (descending order) :
Potassium, sodium, calcium, Magnesium, aluminum, zinc, iron, lead, copper, mercury, silver, platinum, gold
The more reactive an element is, the harder it is to extract it from their ore.
In order to extract iron from iron(ii) oxide, we must heat it with carbon, so that carbon can form carbon dioxide with oxygen, so that iron is extracted. On the other hand, we just need to hear copper oxide in the air in order to extract copper metal.
Because of the difference in extracting the metals, we can know that why iron tools are more difficult to obtain than the copper ones.
Answer:
could you please list the phrases
Answer :
'n' specifies → (B) The energy and average distance from the nucleus.
'l' specifies → (C) The subshell orbital shape.
'ml' specifies → (A) The orbital orientation.
Explanation :
Principle Quantum Numbers : It describes the size of the orbital. It is represented by n. n = 1,2,3,4....
Azimuthal Quantum Number : It describes the shape of the orbital. It is represented as 'l'. The value of l ranges from 0 to (n-1). For l = 0,1,2,3... the orbitals are s, p, d, f...
Magnetic Quantum Number : It describes the orientation of the orbitals. It is represented as
. The value of this quantum number ranges from
. When l = 2, the value of
Spin Quantum number : It describes the direction of electron spin. This is represented as
. The value of this is
for upward spin and
for downward spin.
As per question we conclude that,
'n' specifies → The energy and average distance from the nucleus.
'l' specifies → The subshell orbital shape.
'ml' specifies → The orbital orientation.
Answer : The value of
at this temperature is 66.7
Explanation : Given,
Pressure of
at equilibrium = 0.348 atm
Pressure of
at equilibrium = 0.441 atm
Pressure of
at equilibrium = 10.24 atm
The balanced equilibrium reaction is,

The expression of equilibrium constant
for the reaction will be:

Now put all the values in this expression, we get :


Therefore, the value of
at this temperature is 66.7