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2 years ago

State which substance is undergoing oxidation and which substance is undergoing reduction in the following reaction:

Chemistry

1 answer:

n200080 [17]2 years ago

5 0

Fe is undergoing oxidation while S is undergoing reduction

<h3>What is oxidation-reduction reaction?</h3>

Oxidation-reduction reaction can simply be defined as a special type of chemical reaction in which the oxidation states of substrate change. Oxidation is the

So therefore, Fe is undergoing oxidation while S is undergoing reduction

Learn more about oxidation-reduction reaction:

brainly.com/question/17109097

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What type of bonding is found in the molecule HBr?

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D)polar covalent because ionic and metallics include metals and nonpolar covalent wouldn’t work because it’s lewis for structure and en doesn’t match its requirements.

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3 years ago

What conclusion can be draw about the heat of fusion of water from the heating curve? A) The potential energy of fusion represen

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3 years ago

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How much heat will be released when 10.0 g of hydrogen peroxide decomposes according to the following reaction: 2H2O2(l) 2H2O(l)

kramer

C. 28 KJ

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3 years ago

What volume (in liters) of a solution contains 0.14 mol of KCl?

oksano4ka [1.4K]

Answer:

$\boxed {\boxed {\sf 0.078 \ L }}$

Explanation:

We are asked to find the volume of a solution given the moles of solute and molarity.

Molarity is a measure of concentration in moles per liter. It is calculated using the following formula:

$molarity= \frac{moles \ of \ solute}{liters \ of \ solution}$

We know there are 0.14 moles of potassium chloride (KCl), which is the solute. The molarity of the solution is 1.8 molar or 1.8 moles of potassium chloride per liter.

moles of solute = 0.14 mol KCl
molarity= 1.8 mol KCl/ L
liters of solution=x

Substitute these values/variables into the formula.

$1.8 \ mol \ KCl/ L = \frac { 0.14 \ mol \ KCl}{x}$

We are solving for x, so we must isolate the variable. First, cross multiply. Multiply the first numerator and second denominator, then the first denominator and second numerator.

$\frac {1.8 \ mol \ KCl/L}{1} = \frac{0.14 \ mol \ KCl}{x}$

$1.8 \ mol \ KCl/ L *x = 1*0.14 \ mol \ KCl$

$1.8 \ mol \ KCl/ L *x = 0.14 \ mol \ KCl$

Now x is being multiplied by 1.8 moles of potassium chloride per liter. The inverse operation of multiplication is division, so we divide both sides by 1.8 mol KCl/L.

$\frac {1.8 \ mol \ KCl/ L *x}{1.8 \ mol \ KCl/L} = \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}$

$x= \frac{0.14 \ mol \ KCl}{1.8 \ mol \ KCl/L}$

The units of moles of potassium chloride cancel.

$x= \frac{0.14 }{1.8 L}$

$x=0.07777777778 \ L$

The original measurements of moles and molarity have 2 significant figures, so our answer must have the same. For the number we found, that is the thousandth place. The 7 in the ten-thousandth place tells us to round the 7 up to a 8.

$x \approx 0.078 \ L$

There are approximately <u>0.078 liters of solution.</u>

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3 years ago

Complete the statement<br>qxy- bxy+cxy= xy( )

andrey2020 [161]

Answer:

xy (-b+c+q) is the answer to this

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3 years ago