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2 years ago

I need help with my work

Chemistry

1 answer:

ValentinkaMS [17]2 years ago

7 0

Answer: D. 3Ag+ + PO43- = Ag3PO4

Explanation:

Overall Chemical Equation:

Ensure that the elements on both sides of the equation are balanced.

3C2H3AgO2 + Na3O4P = Ag3PO4 + 3C2H3NaO2

Solubility Equation:

Determine the state or phase of each substance (gas=g, liquid=l, solid/non-soluble=s, aqueous/soluble=aq) in its undissociated form.

3C2H3AgO2(aq) + Na3O4P(aq) = Ag3PO4(s) + 3C2H3NaO2(aq)

Complete Ionic Equation:

The complete ionic equation includes spectator ions. Write it by breaking all the soluble ionic compounds into their respective ions.

3Ag+(aq) + 3CH3COO-(aq) + 3Na+(aq) + PO43-(aq) = Ag3PO4(s) + 3Na+(aq) + 3CH3COO-(aq)

Net Ionic Equation:

The balanced net ionic equation includes only species that are involved in the reaction. It can be found by removing ions that occur on both the reactant and product side of the complete ionic equation.

3Ag+(aq) + PO43-(aq) = Ag3PO4(s)

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If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?

myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

$t_{1/2}=\frac {ln\ 2}{k}$

Where, k is rate constant

So,

$k=\frac{\ln2}{t_{1/2}}$

$k=\frac{\ln2}{30.17}\ year^{-1}$

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

$[A_t]=[A_0]e^{-kt}$

Where,

$[A_t]$ is the concentration at time t

$[A_0]$ is the initial concentration

Initial concentration $[A_0]$ = ?

Final concentration $[A_t]$ = 12.5 grams

Applying in the above equation, we get that:-

$12.5\ g=[A_0]e^{-0.02297\times 90.6}$

$[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g$

<u>Mass of original sample = 100 g</u>

8 0

3 years ago

Calculate the standard enthalpy change of formation of CHA given that the standard enthalpies change of combustion of methane, g

Nostrana [21]

Answer : The standard enthalpy of formation of methane is, -74.8 kJ/mole

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The formation reaction of $CH_4$ will be,

$C(s)+2H_2(g)\rightarrow CH_4(g)$ $\Delta H_{formation}=?$

The intermediate balanced chemical reaction will be,

(1) $CH_4(g)+2O_2(g)\rightarrow CO_2(g)+2H_2O(l)$ $\Delta H_1=-890kJ/mole$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.4kJ/mole$

(3) $H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)$ $\Delta H_3=-285.7kJ/mole$

Now we will reverse the reaction 1, multiply reaction 3 by 2 then adding all the equations, we get :

(1) $CO_2(g)+2H_2O(l)\rightarrow CH_4(g)+2O_2(g)$ $\Delta H_1=890kJ/mole$

(2) $C(s)+O_2(g)\rightarrow CO_2(g)$ $\Delta H_2=-393.4kJ/mole$

(3) $2H_2(g)+2O_2(g)\rightarrow 2H_2O(l)$ $\Delta H_3=2\times (-285.7kJ)=-571.4kJ/mole$

The expression for enthalpy of formation of $CH_4$ will be,

$\Delta H_{formation}=\Delta H_1+\Delta H_2+\Delta H_3$

$\Delta H=(+890kJ/mole)+(-393.4kJ/mole)+(-571.4kJ/mole)$

$\Delta H=-74.8kJ/mole$

Therefore, the standard enthalpy of formation of methane is, -74.8 kJ/mole

3 0

3 years ago

Solve using significant figures <br> 8.647 + 45.969

Murrr4er [49]

Answer:

54.616

Explanation:

8.647 + 45.969

or rewrite for easier look:

45.969 +

8.647 =

54.616

Hope this helped :3

5 0

4 years ago

Read 2 more answers

Lab activity - Law of Conservation of Mass with vinegar and baking soda.

lesya [120]

Answer: I BIG DUMB

Explanation:

7 0

3 years ago

Place the following in correct sequence from simplest to most complex: 1. molecules 2. atoms 3. tissues 4. cells 5. organs

Lera25 [3.4K]

Answer:

Simplest to complex

Atoms, molecules, cells, tissues, organs

Explanation:

An atom is the smallest or basic unit of any substance or thing. therefore, it is simplest among given.

Two or more atoms joined together to form molecules. Therefore, molecules are complex than atoms.

Cell is the basic unit of life and a cell is made of many molecules and compounds. So, cells are more complex than molecules.

Several cells organised in a definite way to form tissue, so tissues are group of cells and perform a definite function inside a living thing. So, tissues are more complex than cell.

Organs consist of several cells and tissues and perform a specific functions. Therefore, organs are the most complex structure among given.

Therefore order from simplest to complex is as follows:

Atoms, molecules, cells, tissues, organs

6 0

4 years ago