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Talja [164]
3 years ago
13

Lab activity - Law of Conservation of Mass with vinegar and baking soda.

Chemistry
1 answer:
lesya [120]3 years ago
7 0

Answer: I BIG DUMB

Explanation:

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A student claims that if she wanted to make a solution quickly, she should use small pellets instead of powder along with heatin
vova2212 [387]

Answer: Yes we agree with the student's claim.

Explanation:

When the molecules are present in smaller size, more reactants can react as decreasing the size increases the surface area of the reactants which will enhance the contact of molecules.Hence, more products will form leading to increased rate of reaction.

On increasing the temperature will make more reactant molecules will have sufficient energies to cross the energy barrier and thus the number of effective collisions increases, thus leading to more products and increased rate of reaction.

When the solution is stirred , the molecule's kinetic energy and thus the rate of reaction increases.

Thus smaller size, stirring and increase of temperature will make the solution quickly.

7 0
3 years ago
This is the chemical formula for Chormium (III) nitrate Cr(NO3)3Calculate the mass percent of nitrogen in chromium(III) nitrate.
butalik [34]

Answer:

The percent composition for nitrogen in chromium(III) nitrate is 6%.

Explanation:

6 0
3 years ago
The radios of a atom is defined as
telo118 [61]

Answer:

Atomic radius...........

6 0
3 years ago
What law allows calories to be determined by heat (energy) transfer from one substance to another, but it is never destroyed?
Mila [183]

Answer:

matter i think

Explanation:

matter i am pretty sure

6 0
3 years ago
An 18 liter container holds 16.00 grams of oxygen gas (o2 at 45 °c. what is the pressure in the container?
Scrat [10]
Hello!

The pressure of an 18 L container which holds 16,00 grams of oxygen gas (O₂) at 45 °C is 0,725 atm

To solve this problem we first need to set up the data in the appropriate units to input it in the Ideal Gas Law.

a) 16 g of Oxygen gas to moles of oxygen gas:

16gO_2* \frac{1 mol O_2}{32gO_2}=0,5 mol O_2

b) 45 °C to K

K=$^{\circ}$C + 273,15 = 45 $^{\circ}$C + 273.15=318,15 K

Now, we clear the Ideal Gas Equation for P, and solve it:

P*V=n*R*T \\ \\ P= \frac{n*R*T}{V}= \frac{(0,5mol)*(0,082 \frac{L*atm}{mol*K})* (318,15 K)}{18 L}= 0,725 atm

Have a nice day!
4 0
3 years ago
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