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kobusy [5.1K]
2 years ago
7

Calculate the pH of the following:

Chemistry
1 answer:
Brums [2.3K]2 years ago
6 0

The pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution.

<h3>What is the pH?</h3>

What we call the pH can be defined as the negative logarithm of the hydrogen ion concentration of the solution. We are aware that we can use the relation [H+]  [OH-]  = 1 * 10^-14 to handle the enormity of this problem.

Now, let us go about solving the problems;

1. pH = -log(1 x 10-7) = 7

2.  [H+]=  1 * 10^-14/ 1 x 10^-3

pH =  -log(  1 * 10^-11)

pH = 11

3. pH = -log( 1 x 10^-2)

pH = 2

4. pH = -log(  1 x 10^-10)

pH = 10

5.  [H+]=  1 * 10^-14/ 1 x 10^-8

[H+]=  1 * 10^-6

pH = 6

Learn more about pH:brainly.com/question/1528974

#SPJ1

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100.0 mL of Ca(OH)2 solution is titrated with 5.00 x 10–2 M HBr. It requires 36.5 mL of the acid solution for neutralization. Wh
miskamm [114]

Answer:

The number of moles HBr = 0.001825

The concentration of Ca(OH)2 = 0.009125 M

Explanation:

Step 1: Data given

Volume of the Ca(OH)2 = 100.0 mL = 0.100 L

Molarity of HBr = 5.00 * 10^-2 M

Volume of HBR = 36.5 mL = 0.0365 L

Step 2: The balanced equation

Ca(OH)2 + 2HBr → CaBr2 + 2H2O

Step 3: Calculate molarity of Ca(OH) 2

b*Va* Ca = a * Vb*Cb

⇒with b = the coefficient of HBr = 2

⇒with Va = the volume of Ca(OH)2 = 0.100 L

⇒with ca = the concentration of Ca(OH)2 = TO BE DETERMINED

⇒with a = the coefficient of Ca(OH)2 = 1

⇒with Vb = the volume of HBr = 0.0365 L

⇒with Cb = the concentration of HBr = 5.00 * 10^-2 = 0.05 M

2 * 0.100 * Ca = 1 * 0.0365 * 0.05

Ca = (0.0365*0.05) / 0.200

Ca = 0.009125 M

Step 4: Calculate moles HBr

Moles HBr = concentration HBr * volume HBr

Moles HBr = 0.05 M * 0.0365 L

Moles HBr = 0.001825 moles

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