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baherus [9]
3 years ago
8

How do I answer this???

Chemistry
1 answer:
Mumz [18]3 years ago
8 0
Will you have to show me what you're talking
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When zinc nitrate is heated, zinc oxide, nitrogen dioxide(NO2) and oxygen gas are
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Answer:

i) 16.5g of ZnO

ii) 9.8 dm³ of NO2

Explanation:

The working is shown in the photo so kindly refer to it

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3 years ago
A target is shielded from a radioactive sample by a sheet of metal. What kind of radiation can pass through the sheet of metal a
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A. o. I know gamma can I Hope this helps


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4 0
3 years ago
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Name two compounds in unpolluted air?
elena-14-01-66 [18.8K]

The two compounds present in unpolluted air are carbon dioxide and water. You may think that carbn dioxide is a greenhouse gas, yes it is and at the same time not. There animals in the earth that produces carbon dioxide into the atmosphere, the carbon dioxide too, is also need for plan respiration. 

3 0
3 years ago
pls help!!! Calculate the pH of a solution with a H+ ion concentration of 2.6 x 10^-7 and round your answer to the nearest hundr
earnstyle [38]

Answer:

6.59

Explanation:

pH=-log[H+]

=-log[2.6×10^-7]

=6.59

8 0
3 years ago
Let us write the appropriate equilibria and associate the correction <img src="https://tex.z-dn.net/?f=K_b" id="TexFormula1" tit
rosijanka [135]

Explanation:

The relation between K_a\&K_b is given by :

K_w=K_a\times K_b

Where :

K_w=1\times 10^{-14} = Ionic prodcut of water

The value of the first ionization constant of sodium sulfite = K_{a1}=1.4\times 10^{-2}

The value of K_{b1}:

1\times 10^{-14}=1.4\times 10^{-2}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{1.4\times 10^{-2}}=7.1\times 10^{-13}

The value of the second ionization constant of sodium sulfite = K_{a2}=6.3\times 10^{-8}

The value of K_{b2}:

1\times 10^{-14}=6.3\times 10^{-8}\times K_{b1}

K_{b1}=\frac{1\times 10^{-14}}{6.3\times 10^{-8}}=1.6\times 10^{-7}

3 0
3 years ago
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