Answer:
10.08 L.
Explanation:
- If we assume that CO₂ gas behaves ideally at STP (standard T(0.0 °C) and P(1.0 atm)):
<em>It is known that 1.0 mole of ideal gas occupies 22.4 L at STP conditions.</em>
<em></em>
<u><em>Using cross multiplication:</em></u>
1.0 mole of CO₂ gas occupies → 22.4 L.
0.45 mole of CO₂ gas occupies → ??? L.
<em>∴ The volume occupied by 0.45 mole of CO₂ gas </em>= (0.45 mol)(22.4 L)/(1.0 mol) = <em>10.08 L.</em>
Answer:
See figure 1
Explanation:
On this case we have a <u>base</u> (methylamine) and an <u>acid</u> (2-methyl propanoic acid). When we have an acid and a base an <u>acid-base reaction </u>will take place, on this specific case we will produce an <u>ammonium carboxylate salt.</u>
Now the question is: <u>¿These compounds can react by a nucleophile acyl substitution reaction?</u> in other words <u>¿These compounds can produce an amide? </u>
Due to the nature of the compounds (base and acid), <u>the nucleophile</u> (methylamine) <u>doesn't have the ability to attack the carbon</u> of the carbonyl group due to his basicity. The methylamine will react with the acid-<u>producing a positive charge</u> on the nitrogen and with this charge, the methylamine <u>loses all his nucleophilicity.</u>
I hope it helps!
Number one: True Number 2: False because hot stars apear as blue-white and cool stars apear as red
Answer:
- C. it is a strong acid since the blue litmus paper turns red and the pH is 1.7
Explanation:
As per table gastric juice has pH of 1.7 which is the strong acid. If you remember, 0-7 range determines acids and litmus paper confirms that by turning red.
So correct choice is C.