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Ad libitum [116K]
2 years ago
6

Example of a solid that sunlines is ( ? )

Physics
1 answer:
Arturiano [62]2 years ago
5 0

An example of a solid that sunlines is a billboard.

<h3>What is a billboard?</h3>

A billboard simply refers to a very large board which is usually, frequently and most of the time used for displaying advertisements

So therefore, an example of a solid that sunlines is a billboard

Learn more about billboard:

brainly.com/question/26961773

#SPJ1

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Consider the video tutorial you just watched. Suppose that we duplicate this experimental setup in an elevator. What will the sp
zloy xaker [14]

Explanation:

if the elevator is moving upward with the constant speed the spring scale will read 18 N which is the mass of each of the two blocks attached by separate springs to the scale at opposite ends.

4 0
3 years ago
10.<br> Name THREE conductors and insulators with examples from everyday use.
Anna35 [415]

Answer:

Explanation:

Some common conductors are copper, aluminum, gold, and silver. Some common insulators are glass, air, plastic, rubber, and wood.

7 0
3 years ago
What is the mathematical relationship among voltage current and resistance​
loris [4]

Answer:

The relationship between voltage, current, and resistance is described by Ohm's law. This equation, i = v/r, tells us that the current, i, flowing through a circuit is directly proportional to the voltage, v, and inversely proportional to the resistance, r.

5 0
3 years ago
Two satellites are in circular orbits around the earth. The orbit for satellite A is at a height of 403 km above the earth’s sur
BARSIC [14]

Answer:

v_A=7667m/s\\\\v_B=7487m/s

Explanation:

The gravitational force exerted on the satellites is given by the Newton's Law of Universal Gravitation:

F_g=\frac{GMm}{R^{2} }

Where M is the mass of the earth, m is the mass of a satellite, R the radius of its orbit and G is the gravitational constant.

Also, we know that the centripetal force of an object describing a circular motion is given by:

F_c=m\frac{v^{2}}{R}

Where m is the mass of the object, v is its speed and R is its distance to the center of the circle.

Then, since the gravitational force is the centripetal force in this case, we can equalize the two expressions and solve for v:

\frac{GMm}{R^2}=m\frac{v^2}{R}\\ \\\implies v=\sqrt{\frac{GM}{R}}

Finally, we plug in the values for G (6.67*10^-11Nm^2/kg^2), M (5.97*10^24kg) and R for each satellite. Take in account that R is the radius of the orbit, not the distance to the planet's surface. So R_A=6774km=6.774*10^6m and R_B=7103km=7.103*10^6m (Since R_{earth}=6371km). Then, we get:

v_A=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{6.774*10^6m} }=7667m/s\\\\v_B=\sqrt{\frac{(6.67*10^{-11}Nm^2/kg^2)(5.97*10^{24}kg)}{7.103*10^6m} }=7487m/s

In words, the orbital speed for satellite A is 7667m/s (a) and for satellite B is 7487m/s (b).

7 0
2 years ago
Which are characteristics of scientific questions? Check all that apply.
barxatty [35]

Answer:

A B and D

Explanation:

7 0
3 years ago
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