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Ad libitum [116K]
2 years ago
6

Example of a solid that sunlines is ( ? )

Physics
1 answer:
Arturiano [62]2 years ago
5 0

An example of a solid that sunlines is a billboard.

<h3>What is a billboard?</h3>

A billboard simply refers to a very large board which is usually, frequently and most of the time used for displaying advertisements

So therefore, an example of a solid that sunlines is a billboard

Learn more about billboard:

brainly.com/question/26961773

#SPJ1

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Acceleration causes a shift of weight to the ______.
marta [7]
Vehicle weight shifts can be backward forward. In this particular case accelerating to fast would cause a shift of weight backwards. Breaking too quickly on the other hand would cause weight to shift forward. You have seen this while in a car or a bus at the traffic light. As the vehicle breaks you are pulled forward as it starts moving you are pulled backwards.  
7 0
3 years ago
Why are less massive stars thought to age more slowly than more massive stars have much less fuel?
docker41 [41]
The reason being nuclear reactions are slow in less massive stars than in massive stars hence they age slowly.
8 0
4 years ago
Please guys i need help in this
JulijaS [17]

Answer:

10 seconds

Explanation:

We have the equation V = at  (speed = acceleration x time)

We want to find the time, so can rearrange to T = V/a (time = speed / acceleration).

From the question, we know V is 5 and a is 0.5.

Now we can substitute that into our equation: 5/0.5 = 10.

So the time is 10 seconds.

Hope this helps! Let me know if you have any questions :)

8 0
3 years ago
An electron of mass 9.11 x 10^-31 kg has an initial speed of 4.00 x 10^5 m/s. It travels in a straight line, and its speed incre
yarga [219]

Answer:

a.     F = 2.32*10^-18 N

b.     The force F is 2.59*10^11 times the weight of the electron

Explanation:

a. In order to calculate the magnitude of the force exerted on the electron you first calculate the acceleration of the electron, by using the following formula:

v^2=v_o^2+2ax         (1)

v: final speed of the electron = 6.60*10^5 m/s

vo: initial speed of the electron = 4.00*10^5 m/s

a: acceleration of the electron = ?

x: distance traveled by the electron = 5.40cm = 0.054m

you solve the equation (2) for a and replace the values of the parameters:

a=\frac{v^2-v_o^2}{2x}=\frac{(6.60*10^5m/s)^2-(4.00*10^5m/s)^2}{2(0.054m)}\\\\a=2.55*10^{12}\frac{m}{s^2}

Next, you use the second Newton law to calculate the force:

F=ma

m: mass of the electron = 9.11*10^-31kg

F=(9.11*10^{-31}kg)(2.55*10^{12}m/s^2)=2.32*10^{-18}N

The magnitude of the force exerted on the electron is 2.32*10^-18 N

b. The weight of the electron is given by:

F_g=mg=(9.11*10^{-31}kg)(9.8m/s^2)=8.92*10^{-30}N

The quotient between the weight of the electron and the force F is:

\frac{F}{F_g}=\frac{2.32*10^{-18}N}{8.92*10^{-30}N}=2.59*10^{11}

The force F is 2.59*10^11 times the weight of the electron

8 0
3 years ago
What is two thirds of 27
Ahat [919]
The answer is 18

27/3 x 2 = 18
7 0
4 years ago
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