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yarga [219]
2 years ago
15

An object is thrown upward with initial velocity of 30m/s at angle of 30 degree to the horizontal. calculate the components of t

he initial velocity.​
Physics
1 answer:
mel-nik [20]2 years ago
5 0

Answer:

Vo (vertical) = Vo sin 30 = 30 m/s / 2 = 15 m/s

Vo (horizontal) = Vo cos 30 = .866 30 m/s = 26 m/s

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A 2.3 m long wire weighing 0.075 N/m is suspended directly above an infinitely straight wire. The top wire carries a current of
ZanzabumX [31]

Answer:

Explanation:

Magnetic field near current carrying wire

= \frac{\mu_0}{4\pi} \frac{2i}{r}

i is current , r is distance from wire

B =  10⁻⁷ x \frac{2\times49}{r}

force on second wire per unit length

B I L , I is current in second wire , L is length of wire

=  10⁻⁷ x \frac{2\times49}{r} x 33 x 1

= 3234 x \frac{10^{-7}}{r}

This should balance weight of second wire per unit length

3234 x \frac{10^{-7}}{r} = .075

r = \frac{3234}{.075} x 10⁻⁷

= .0043 m

= .43 cm .

5 0
3 years ago
How can the IMA of a first- class lever be increased?
Dimas [21]
IMA = Ideal Mechanical Advantage

First class lever = > F1 * x2 = F2 * x1

Where F1 is the force applied to beat F2. The distance from F1 and the pivot is x1 and the distance from F2 and the pivot is x2

=> F1/F2 = x1 /x2

IMA = F1/F2 = x1/x2

Now you can see the effects of changing F1, F2, x1 and x2.

If you decrease the lengt X1 between the applied effort (F1) and the pivot,  IMA decreases.

If you increase the length X1 between the applied effort (F1) and the pivot, IMA increases.

If you decrease the applied effort (F1) and increase the distance between it and the pivot (X1) the new IMA may incrase or decrase depending on the ratio of the changes.

If you decrease the applied effort (F1) and decrease the distance between it and the pivot  (X1) IMA will decrease.

Answer: Increase the length between the applied effort and the pivot.
4 0
4 years ago
Read 2 more answers
Electricity is the movement of _____ from one atom to another along a conductor.
prohojiy [21]

The sentence can be completed as follows:

"Electricity is the movement of charges from one atom to another along a conductor."


The movement of the the charges is due to the presence of a potential difference across the conductor, which pushes the charges. More specifically, in normal conductors, the carriers of electricity are the electrons. Therefore we can rewrite the sentence as

"Electricity is the movement of electrons from one atom to another along a conductor."

4 0
3 years ago
Which of the following is not possible? A. Gas flow equals pressure gradient over resistance. B. Resistance equals pressure grad
kaheart [24]

Answer:

C. Pressure gradient equals gas flow over resistance.

Explanation:

As we know that pressure gradient is the driving force for the gas to flow from one point to other point

And we know that the flow rate is directly proportional to the driving force and it inversely depends on the resistance to flow

so we can say

Flow Rate = \frac{Driving \: force}{Resistance}

Flow Rate = \frac{Pressure \: Gradient}{Resistance}

so we can say that correct statements are as below

A. Gas flow equals pressure gradient over resistance.

B. Resistance equals pressure gradient over gas flow.

D. The amount of gas flowing in and out of the alveoli is directly proportional to the difference in pressure or pressure gradient between the external atmosphere and the alveoli.

5 0
3 years ago
A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to s
Flura [38]

Answer:

Refer to the attachment for solution (1).

<h3><u>Calculating time taken by it to stop (t) :</u></h3>

By using the second equation of motion,

→ v = u + at

  • v denotes final velocity
  • u denotes initial velocity
  • t denotes time
  • a denotes acceleration

→ 0 = 5 + (-5/6)t

→ 0 = 5 - (5/6)t

→ 0 + (5/6)t = 5

→ (5/6)t = 5

→ t = 5 ÷ (5/6)

→ t = 5 × (6/5)

→ t = 6 seconds

→ Time taken to stop = 6 seconds

7 0
3 years ago
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