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yarga [219]
2 years ago
15

An object is thrown upward with initial velocity of 30m/s at angle of 30 degree to the horizontal. calculate the components of t

he initial velocity.​
Physics
1 answer:
mel-nik [20]2 years ago
5 0

Answer:

Vo (vertical) = Vo sin 30 = 30 m/s / 2 = 15 m/s

Vo (horizontal) = Vo cos 30 = .866 30 m/s = 26 m/s

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During each heartbeat, about 80 g of blood is pumped into the aorta inapproximately 0.2 s. During this time, the blood is accele
taurus [48]

Answer:

Work is done by the heart on the blood during this time is 0.04 J

Explanation:

Given :

Mass of blood pumped, m = 80 g = 0.08 kg

Initial speed of the blood, u = 0 m/s

Final speed of the blood, v = 1 m/s

Initial kinetic energy of blood is determine by the relation:

E_{1}=\frac{1}{2} m u^{2}

Final kinetic energy of blood is determine by the relation:

E_{2}=\frac{1}{2} m v^{2}

Applying work-energy theorem,

Work done = Change in kinetic energy

W = E₂ - E₁

W=\frac{1}{2} m (v^{2}-u^{2})

Substitute the suitable values in the above equation.

W=\frac{1}{2}\times0.08\times (1^{2}-0^{2})

W = 0.04 J

6 0
3 years ago
Dr. Smith is conducting an experiment to determine if paintings of landscapes produce more peaceful feelings than abstract paint
skad [1K]

The option that could be the hypothesis for this experiment is that D. Abstract paintings may elicit feelings of stress as students try to determine the meanings of the paintings; therefore, abstract paintings may cause college students to report lower feelings of peace.

<h3>What is a hypothesis?</h3>

It should be noted that a hypothesis simply means the proposed explanation made on the basis of limited evidence.

From the information, Smith is conducting an experiment to determine if paintings of landscapes produce more peaceful feelings than abstract paintings.

Therefore, the option that could be the hypothesis for this experiment is that abstract paintings may elicit feelings of stress as students try to determine the meanings of the paintings; therefore, abstract paintings may cause college students to report lower feelings of peace.

Learn more about hypothesis on:

brainly.com/question/11555274

#SPJ1

3 0
2 years ago
.A hard rubber ball, released at chest height, falls to the pavement and bounces back to nearly the same height. When it is in c
ohaa [14]

Answer:

 a = 1.1 10⁵ m / s²

Explanation:

This is a momentum exercise, where we use the relationship between momentum and momentum

          I = ∫ F dt = Δp

= p_f - p₀

as they indicate that the ball bounces at the same height, we can assume that the moment when it reaches the ground is equal to the moment when it bounces, but in the opposite direction

        F t = 2 (m v)

therefore the average force is

         F = 2 m v / t

where in general the mass of the ball unknown, the velocity of the ball can be calculated using the conservation of energy

starting point. Done the ball is released with zero initial velocity

        Em₀ = U = mgh

final point. Upon reaching the ground, just before the deformation begins

        Em_f = K = ½ m v²

energy is conserved in this system

        Em₀ = Em_f

        m g h = ½ m v²

        v = √ (2gh)

This is the velocity of the body when it reaches the ground, so the force remains

        F = 2m √(2gh)   /t

where the height of the person's chest is known and the time that the impact with the floor lasts must be estimated in general is of the order of milli seconds

knowing this force let's use Newton's second law

          F = m a

          a = F / m

 

          a = 2 √(2gh) / t

We can estimate the order of magnitude of this acceleration, assuming the person's chest height of h = 1.5 m and a collision time of t = 1 10⁻³ s

         a = 2 √ (2 9.8 1.5) / 10⁻³

         a = 1.1 10⁵ m / s²

6 0
3 years ago
You look down an old well, cannot see the bottom, and mutter to yourself "Oh well!". In order to estimate the depth of the well,
telo118 [61]

Answer:

The best estimate of the depth of the well is 2.3 sec.

Explanation:

Given that,

Record time,

t_{1}=2.19\ sec

t_{2}=2.30\ sec

t_{3}=2.26\ sec

t_{4}=2.29\ sec

t_{5}=2.27\ sec

We need to find the best estimate of the depth of the well

According to record time,

We can write of the record time

t_{1}=2.19\approx 2.2\ sec

t_{2}=2.30\approx 2.3\ sec

t_{3}=2.26\approx 2.3\ sec

t_{4}=2.29\approx 2.3\ sec

t_{5}=2.27\approx 2.3\ sec

Here, all time is nearest 2.3 sec.

So, we can say that the best estimate of the depth of the well is 2.3 sec.

Hence, The best estimate of the depth of the well is 2.3 sec.

6 0
3 years ago
Anyone wanna join whereby?<br><br> https://whereby.com/dancing-goddess
AleksandrR [38]
Sure let me download it rn
6 0
3 years ago
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