Answer:
Fr = 150 [N]
a = 5 [m/s²]
Explanation:
In order to find the resulting force, we must assume that the thrust force is positive to the right, while the friction force is negative to the left.
![F_{r}=200-50\\F_{r}=150[N]](https://tex.z-dn.net/?f=F_%7Br%7D%3D200-50%5C%5CF_%7Br%7D%3D150%5BN%5D)
Now Newton's Second Law tells us that the sum of the forces or the resulting force is equal to the product of mass by acceleration.
F = m*a
![150 = 30*a\\a=150/30\\a = 5 [m/s^{2} ]](https://tex.z-dn.net/?f=150%20%3D%2030%2Aa%5C%5Ca%3D150%2F30%5C%5Ca%20%3D%205%20%5Bm%2Fs%5E%7B2%7D%20%5D)
Answer:
0.872<em>m/s</em>
Explanation:
Tangential velocity is given by the formula,
In the question given,
radius= 25meters
time= 180secs
pie= 3.14
number of laps= 1
The magnitude of tangential velocity equals;
<em>v </em>= 157<em>m</em>/180<em>secs</em>
Therefore, the magnitude of the tangential velocity
=0.872<em>m/secs</em>
The baseball because it has a greater mass and would go farther because it don't have holes for the air to go through and slow it down
This is a projectile motion problem, so, we use the formula for trajectory:
y =xtanα + gx^2/2v^2(cosα)^2
where
y is the vertical distance (y = 50 m)
x is the horizontal distance (x=90 m)
α is the angle of trajectory; since it levels of HORIZONTALLY, α = 0°
v is the initial velocity
g is the acceleration due to gravity which is 9.81 m/s^2
Substituting to the formula,
50 =90tan(0°) + (9.81)(90)^2/2v^2(cos0°)^2
v = 28.2 m/s
It's called an action plan
As long as we could organize what actions that are going to be taken, when, where, and what could we achieve by that action, basically we can use anything as an action plan
Action plan is different from a to - do list because an action plan is goal oriented. As long as the goal already accomplished, we don't necessarily have to follow the remaining steps
