Explanation:
The given data is as follows.
q = 6.0 nC = 
inner radius (r) = 1.0 cm = 0.01 m (as 1 cm = 100 m)
So, there will be same charge on the inner surface as the charge enclosed with an opposite sign.
Formula to calculate the charge density is as follows.
.......... (1)
Since, area of the sphere is as follows.
A =
........... (2)
Hence, substituting equation (2) in equation (1) as follows.

=
= 
or, = 4.77 
Thus, we can conclude that the resulting charge density on the inner surface of the conducting sphere is 4.77
.
Answer:
low amplitude hope it will help you
Answer:
his results in the final angle after the collision of 37.2 degrees basically what we did there is turn the vector into a right triangle. We use sohcahtoa to solve for the angle. Being.
Explanation:
Answer:
2.84 seconds
Explanation:
t = ?
distance = 125
Velocity origianal = 60 m/hr = 88 ft/s
AVERAGE velocity = 88/2 = 44 ft/s
44 t = 125
t = 125/44 = 2.84 s
Answer:
86.6 lbs
Explanation:
Let the force is X.
Resultant force, R = 100 lbs
Other force is Y. Angle between resultant force and force X is 30°.
According to the diagram


X = 86.6 lbs
Other force Y


Y = 50 lbs