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damaskus [11]
3 years ago
5

Help please!!!

Physics
1 answer:
TiliK225 [7]3 years ago
7 0

Answer:

Cu 8.92

Explanation:

The formula for density is mass/volume. If you were to divide 62.44 by 7, you would get 8.92. Since copper is the only metal in this table that has a density of 8.92, that is the answer.

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Is the water the same temperature in alaska and mexico?
Snezhnost [94]
Colder in Alaska, warmer in Mexico. 
6 0
3 years ago
True or False? In an RL circuit, the larger the value of R (i.e. the resistance of the circuit), the longer it takes the circuit
Luba_88 [7]

Answer:

1.False

2.4 E

Explanation:

1.We have to find the statement is true or false.

We know that

Time constant,\tau=\frac{L}{R}

Time constant is inversely proportional to resistance R .It means when R increases then time constant decreases when R decrease then the time  constant decreases.

Statement:The larger the value of R ,the longer it takes the circuit to reach its final steady- state value

It is false.

2.Energy stored in inductor,E=\frac{1}{2}LI^2

When I'=2I

Then, E'=\frac{1}{2}L(2I)^2=\frac{1}{2}LI^2\times 4=4 E

Hence,the new total energy will become 4 E.

3 0
3 years ago
A small candle is 34 cm from a concave mirror having a radius of curvature of 22 cm. Where will the image of the candle be locat
xxTIMURxx [149]

Answer:

16.26 cm in front of the mirror

Explanation:

Using,

1/f = 1/u+1/v....................... Equation 1

Where f = focal focal length of the concave mirror, u = object distance, v = image distance.

make v the subject of the equation

v = fu/(u-f)................... Equation 2

Note: The focal length of a concave mirror is positive

Using the real- is- positive convention

Given: f = 22/2 = 11 cm, u = 34 cm.

Substitute into equation 2

v = (34×11)/(34-11)

v = 374/23

v = 16.26 cm.

The image will be formed 16.26 cm in front of the mirror.

5 0
3 years ago
A lizard ran 3 meters from his rock to his friend's house. He ran
lbvjy [14]

Answer:

4.5 meters

Explanation:

3 meters to his friend's house. +3

Halfway back. +1.5

3+1.5

=4.5

4.5 meters in total

5 0
3 years ago
Read 2 more answers
An air-filled parallel plate capacitor has circular plates with radius r=20.0 cm, separated distance 4.00 mm. The capacitor is c
blsea [12.9K]

Answer: a) 278 * 10^-12 F and 19.4 * 10^-9 C

b) 17.44 * 10^3 N/C and c) C=k*C0 and V=70/k

Explanation: In order to solve this problem we have to use the expression of the capacitor of parallel plates as:

C=A*ε0/d where A is the area of the plates and d the distance between them

C=Π r^2*ε0/d

C=π*0.2^2*8.85*10^-12/0.004=278 * 10^-12F= 278 pF

then

ΔV= Q/C

so Q= ΔV*C=70V*278 pF=19.4 nC

The electric field between the plates is given by:

E= Q/(A*ε0)=19.4 nC/(π*0.2^2*8.85*10^-12)=17.44 *10^3 N/C

If it is introduced a dielectric between the plates, then the new C is increased a factor k while the potential between the plates decreases a factor 1/k.

7 0
3 years ago
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