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KiRa [710]
4 years ago
9

Select the correct electron configurations from the list below. You can refer to the periodic table for atomic numbers. Check al

l that apply.
A) The electron configuration of O2− is [He]2s22p6.
B) The electron configuration of Cs is [Xe]6s05d1.
C) The electron configuration of Ag+ is [Kr]5s14d9.
D) The electron configuration of Si is [Ne]3s23p2.
E) The electron configuration of Ni is [Ar]4s23d8.
Chemistry
1 answer:
Diano4ka-milaya [45]4 years ago
3 0

Answer:

Corrects answer are Option A and Option D

Explanation:

[He]2s22p4 → This is the electron configuration for O, but if you have the anion, oxide it means that it gain 2 electrons. That's why you have 2 more e- in last cape.

[Ne]3s23p2 → The correct electron configuration for Si.

Si is an element from group 14. Its oxidation state is 4-´,

with a tendency to lose 4 electrons, the 2 of level 3s and level 3p. 4 electrons are being necessary to reach the gas noble configuration.

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Explanation:

After they test the hypothesis they come to a conclusion of the answer.

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3 years ago
The radioisotope that has the longest half-life is the best to use in powering planet and space exploration vehicles because the
Diano4ka-milaya [45]

Answer:

U-238

Explanation:

For a given radioisotope, half life can be defined as the time taken for the isotope to decay into one-half of its original amount. Mathematically, this is expressed as:

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where k = rate constant for the radioactive decay process

Greater the t1/2 longer will be its stability.

Based on the given data, U-238 has the largest half life and therefore will be best suited for applications mentioned.

4 0
4 years ago
Read 2 more answers
How many grams of Na2SO4 will be formed from 200.0g of NaOH
nikklg [1K]

The question is incomplete, the complete question is;

Using the following equation 2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq) how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excess of sulfuric acid

Answer:

355.1 g

Explanation:

The equation of the reaction is;

2 NaOH(aq) + H2SO4(aq) → 2 H2O(aq) + Na2SO4(aq)

We have been told that H2SO4 is in excess so NaOH is the limiting reactant. Therefore;

Number of moles in 200g of NaOH = 200g/40g/mol = 5 moles

So;

2 moles of NaOH yields 1 mole of Na2SO4

5 moles of NaOH will yield 5 * 1/2 = 2.5 moles of Na2SO4

Molar mass of Na2SO4 = 142.04 g/mol

Mass of Na2SO4= 2.5 moles * 142.04 g/mol = 355.1 g

8 0
3 years ago
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4 years ago
What is the number of miles in 49.8 mL of 1.0 M NaOH
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5 0
3 years ago
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