The radioisotope that has the longest half-life is the best to use in powering planet and space exploration vehicles because the
y can travel farther. Which radioisotope is the best to use?
2 answers:
Answer:
Uranium-238 is the radioisotope which is best to use.
Explanation:
Half-life : The time in which the concentration of a reactant is reduced to half of its original value is called half life period.
As it has been given that radioisotope that has the longest half-life is best to use as power source planet and space exploration vehicles:
Uranium 238 is with the highest value of half life which is equal to years.
Answer:
U-238
Explanation:
For a given radioisotope, half life can be defined as the time taken for the isotope to decay into one-half of its original amount. Mathematically, this is expressed as:
where k = rate constant for the radioactive decay process
Greater the t1/2 longer will be its stability.
Based on the given data, U-238 has the largest half life and therefore will be best suited for applications mentioned.
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We can divide this problem into 4 steps:
Step 1: Calculate mass of one liter solution from the density
Mass of solution = 1000 ml soln x
=1005 g soln
Step 2: Calculate the mass of acetic acid
Mass of CH₃COOH = 1005 g soln x (5.2 g / 100 g soln) = 52.26 g acetic acid
Step 3: Calculate the moles of acetic acid:
52.26 g acetic x (1 mole acetic / 60 g acetic) = 0.871 mol
step 4: Calculate the molarity of acetic acid:
molarity = moles of acetic / liters of soln = 0.871 / 1 L = 0.871 mole / L
Step 1: Calculate mass of one liter solution from the density
Mass of solution = 1000 ml soln x
Step 2: Calculate the mass of acetic acid
Mass of CH₃COOH = 1005 g soln x (5.2 g / 100 g soln) = 52.26 g acetic acid
Step 3: Calculate the moles of acetic acid:
52.26 g acetic x (1 mole acetic / 60 g acetic) = 0.871 mol
step 4: Calculate the molarity of acetic acid:
molarity = moles of acetic / liters of soln = 0.871 / 1 L = 0.871 mole / L