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2 years ago

When a person is standing upright, the weight of anything being lifted and carried in the hands is first reflected onto the:

Physics

1 answer:

hichkok12 [17]2 years ago

8 0

Pelvic girdle

In human anatomy, the pelvis is a complex of bones that connects the trunk and the legs, supports and balances the trunk, and houses and supports the intestines, the urinary bladder, and the internal organ. It is sometimes referred to as the bony pelvis or the pelvic girdle.
One is located on the left side of the body and the other is located on the right. They come together to make the pelvic girdle, a portion of the pelvis. The hip bones are attached to the upper portion of the skeleton at the sacrum.
The pelvic girdle's main function is to support the upper body's weight while seated and transfer that weight to the lower limbs while standing. For the muscles in the trunk and lower limbs, it functions as attachment point.

To learn more about pelvic girdles please visit -
brainly.com/question/24394348

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A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright

Mariulka [41]

Answer:

$7.55\times 10^{-7} m$

Explanation:

We are given that

d=0.23 mm= $0.23\times 10^{-3} m$

$1mm=10^{-3} m$

Screen is placed from the slits at distance ,L=4.75 m

The bright interference fringes on the screen are separated by 1.56 cm.

$\Delta y=1.56 cm=1.56\times 10^{-2} m$

1 m=100 cm

We have to find the wavelength of laser light.

We know that

$\Delta y=\frac{\lambda L}{d}$

Substitute the values

$1.56\times 10^{-2}=\frac{\lambda\times 4.75}{0.23\times 10^{-3}}$

$\lambda=\frac{1.56\times 10^{-2}\times 0.23\times 10^{-3}}{4.75}$

$\lambda=7.55\times 10^{-7} m$

4 0

3 years ago

What is the magnitude of the free-fall acceleration at a point that is a distance 2R above the surface of the Earth, where R is

ss7ja [257]

Answer:

g' = g/9 = 1.09 m/s²

Explanation:

The magnitude of free fall acceleration at the surface of earth is given by the following formula:

g = GM/R² ----- equation 1

where,

g = free fall acceleration

G = Universal Gravitational Constant

M = Mass of Earth

R = Distance between the center of earth and the object

So, in our case,

R = R + 2 R = 3 R

Therefore,

g' = GM/(3R)²

g' = (1/9) GM/R²

using equation 1:

g' = g/9

g' = (9.8 m/s)/9

3 0

3 years ago

A shovel pushes on dirt and the dirt pushes back on the shovel. The dirt pushing back is

Leno4ka [110]

The dirt pushing back is the 'resistance' force. It RESISTS your attempts to shovel it.

6 0

3 years ago

The velocity of a an object in linear motion changes from +25 meters per second to +15 meters per second in 2.0 seconds.

kodGreya [7K]

Answer:

$-5.0 m/s^2$

Explanation:

Missing question:

What is the object's acceleration?

Solution:

The acceleration of an object is given by

$a=\frac{v-u}{t}$

where

v is the final velocity

u is the initial velocity

t is the time taken for the change in velocity

For the object in this problem,

u = +25 m/s

v = +15 m/s

t = 2.0 s

Substituting,

$a=\frac{15-25}{2}=-5.0 m/s^2$

And the acceleration is negative because its direction is opposite to that of the velocity.

5 0

3 years ago

Why is velocity a vector quantity

Jobisdone [24]

Velocity as a Vector Quantity
Because the person always returns to the original position, the motion would never result in a change in position. Since velocity is defined as the rate at which the position changes, this motion results in zero velocity.

4 0

3 years ago

Read 2 more answers