Im not 100% sure you have to tell me if im wrong or not.
D
B
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What’s the rest of this question?
Answer:
6.9m/s
Explanation:
Given parameters:
Acceleration of the object = 4m/s²
Distance = from x; 2m to x; 8m
Unknown:
Average velocity = ?
Solution:
From the given parameters, we use the right motion equation to solve the problem.
v² = u² + 2aS
v is the final velocity
u is the initial velocity
a is the acceleration
S is the distance covered
Distance = 8m - 2m = 6m
Initial velocity = 0m/s
The final velocity gives us the average velocity in this problem;
v² = 0² + (2 x 4 x 6) = 48
v = √48 = 6.9m/s
Answer:
<h3>0.69</h3>
Explanation:
Using the Newtons law of motion;
Fm is the moving force = 400N
Ff is the frictional force = μR
μ is the coefficient of kinetic friction
R is the reaction = mg
m is the mass
a is the acceleration
The equation becomes;
Hence the coefficient of kinetic friction between the box and floor is 0.69
Answer:
1.082 mm
Explanation:
From the question, we can see that we were given The following
Wavelength of the atoms, λ = 502 nm = 502*10^-9 m
Radius of the screen away from the double slit, r = 1.1 m
We know that Y(20) = 10.2 mm = 10.2*10^-3 m
d = (20 * R * λ) / Y(20)
d = (20 * 1.1 * 502*10^-9)/10.2*10^-3
d = 1.1*10^-5 / 10.2*10^-3
d = 1.082 mm
Therefore, we can say that the distance of separation between the two slits is 1.082 mm
