Here are the choices.
A. 200 m
<span>B. 31.25 m </span>
<span>C. 0.2 m </span>
<span>D. 5 m
</span>Pa = N/m²
<span>m² = N/Pa </span>
<span>12.5 kPa = 12500 Pa </span>
<span>m² = N/Pa </span>
<span>m² = 2500 / 12500 </span>
<span>m² = 0.2 </span>
<span>C. 0.2 m²
</span>
So the correct answer is 0.2m^2
Answer:
Explanation:
The velocity at the inlet and exit of the control volume are same
Calculate the inlet and exit velocity of water jet
The conservation of mass equation of steady flow
since inlet and exit velocity of water jet are equal so the inlet and exit cross section area of the jet is equal
The expression for thickness of the jet
R is the radius
t is the thickness of the jet
D_j is the diameter of the inlet jet
(b)
The negative sign indicate that the direction of the force will be in opposite direction of our assumption
Therefore, the horizontal force is -7603N
I = V / R
Current = (voltage) / (resistance)
Current = (500 V) / (250 ohms)
Current = (500/250) Amperes
<em>Current = 2 Amperes</em>