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4 years ago

Can someone help with these?

Physics

1 answer:

Flauer [41]4 years ago

4 0

Basically, all of these questions use F = ma

m = 80 kg

a = 1.62

Weight = F = 80*1.62 = 129.6

The closest answer is B

Step One

Find the mass here on earth

m = F/a

F = 40 kg

a = 9.2

F = 40/9.2 = 4.34

Now take everything to the moon

F = 20 kg

a = ??

m = 4.34

a = F/m = 20/4.34 = 4.6 m/s^2

m = 40 kg

F = 20 N

a = ??

a = F/m = 20N/40kg = 1/2 m/s^2

Comment

All of these depend on F = m*a. None but the first one talk about vertical forces where gravity would play a part. Moving horizontally means that there is no gravitational force if there is no friction. a = 9.8 has nothing to do with the problem.

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If there's any point in a circuit where the current has a choice
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3 years ago

Una furgoneta circula por una carretera a 55km/h. Diez km atrás , un coche circula en el mismo sentido a 85km/h ¿ En cuanto tiem

statuscvo [17]

Answer:

t = 0.33h = 1200s

x = 18.33 km

Explanation:

If the origin of coordinates is at the second car, you can write the following equations for both cars:

car 1:

$x=x_o+v_1t$ (1)

xo = 10 km

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car 2:

$x'=v_2t$ (2)

v2 = 85km/h

For a specific value of time t the positions of both cars are equal, that is, x=x'. You equal equations (1) and (2) and solve for t:

$x=x'\\\\x_o+v_1t=v_2t\\\\(v_2-v_1)t=x_o\\\\t=\frac{x_o}{v_2-v_1}$

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The position in which both cars coincides is:

$x=(55km/h)(0.33h)=18.33km$

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3 years ago

A race car starting from rest accelerates uniformly at a rare of 4.90 meters per second^2. What is the cars speed after it has t

Vesnalui [34]

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3 years ago

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4 years ago

A projectile is launched

Flauer [41]

The vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

The given parameters;

initial horizontal velocity, vₓ = 16 m/s
initial vertical velocity, $v_y =0$
time interval 1 seconds

The components of the velocity can be horizontal or vertical velocity.

The vertical component of the velocity is affected by acceleration due to gravity while the horizontal component of the velocity is not affected by gravity.

The vertical component of the velocity is calculated as;

$v_y = v_0_y -gt\\\\v_y = 0 - (1\times 9.8)\\\\v_y = -9.8 \ m/s$

The horizontal component of the velocity is constant since it is not affected by gravity.

The horizontal component of the velocity = 16 m/s

Thus, the vertical component of the velocity after the given time is -9.8 m/s while the horizontal component of the velocity is 16 m/s.

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3 years ago