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Ivan
3 years ago
7

Transverse waves travel with a speed of 20 m/s on a string under a tension 0f 6.00 N. What tension is required for a wave speed

of 30.0 m/s on the same string?
Physics
1 answer:
Aleksandr [31]3 years ago
5 0

Answer:

T_2=13.5\ N

Explanation:

Given that,

Speed of transverse wave, v₁ = 20 m/s

Tension in the string, T₁ = 6 N

Let T₂ is the tension required for a wave speed of 30 m/s on the same string. The speed of a transverse wave in a string is given by :

v=\sqrt{\dfrac{T}{\mu}}........(1)

T is the tension in the string

\mu is mass per unit length

It is clear from equation (1) that :

v\propto\sqrt{T}

\dfrac{v_1}{v_2}=\sqrt{\dfrac{T_1}{T_2}}

T_2=T_1\times (\dfrac{v_2}{v_1})^2

T_2=6\times (\dfrac{30}{20})^2

T_2=13.5\ N

So, the tension of 13.5 N is required for a wave speed of 30 m/s. Hence, this is the required solution.

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Science assessment help pls
DENIUS [597]

Answer:

Work Done = W

force = F

Distance = d

W = Fd

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3 0
3 years ago
Read 2 more answers
A football is kicked into the air from an initial height of 4 feet. The height, in feet, of the football above the ground is giv
kakasveta [241]

Answer: 0.5 seconds or 2.625 seconds

Explanation:

At t = 0, The ball is 4 ft above the ground.

The height of the football varies with time in the following way:

s(t) = -16 t² + 50 t + 4

we need to find the time in which the height would of the football would be 25 ft:

⇒25 = -16 t² + 50 t + 4

we need to solve the quadratic equation:

⇒ 16 t² - 50 t + 21 = 0

t = \frac{50 \pm \sqrt{50^2-4\times 16\times 21}}{2\times16}

⇒ t = 0.5 s or 2.625 s

Therefore, at t = 0.5 s or 2.625 s, the football would be 25 ft above the ground.

3 0
3 years ago
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A jet plane travels at 40.8 km at an average speed of 340 m/s calculate how long this journey took- giveyour answer to the neare
Tju [1.3M]

Answer:

2\ \text{minutes}

Explanation:

d = Distance traveled = 40.8 km

s = Speed of jet = 340 m/s

Time is given by

t=\dfrac{d}{s}

\Rightarrow t=\dfrac{40.8\times 10^3}{340}

\Rightarrow t=120\ \text{s}

\Rightarrow t=\dfrac{120}{60}=2\ \text{minutes}

The time taken to complete the journey is 2\ \text{minutes}.

6 0
3 years ago
A car is traveling at 7.0 m/s when the driver applies the brakes. The car moves 1.5 m before it comes to a complete stop. If the
viva [34]

Answer:

d. 6.0 m

Explanation:

Given;

initial velocity of the car, u = 7.0 m/s

distance traveled by the car, d = 1.5 m

Assuming the car to be decelerating at a constant rate when the brakes were applied;

v² = u² + 2(-a)s

v² = u² - 2as

where;

v is the final velocity of the car when it stops

0 = u² - 2as

2as = u²

a = u² / 2s

a = (7)² / (2 x 1.5)

a = 16.333 m/s

When the velocity is 14 m/s

v² = u² - 2as

0 = u² - 2as

2as = u²

s = u² / 2a

s = (14)² / (2 x 16.333)

s = 6.0 m

Therefore, If the car had been moving at 14 m/s, it would have traveled 6.0 m before stopping.

The correct option is d

4 0
3 years ago
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