It is 5.3 x 10^-9 kiloliters.
Hope this helps.
Answer:
The magnification would be "103.55". A further explanation is given below.
Explanation:
The given values are:
Distance between lens and eyepiece,
L = 85 cm
Eyepiece is,
= 123 D
Now,
The refractive power of eye piece will be:
⇒
The length of the telescope will be:
⇒
⇒
On substituting the values, we get
⇒
⇒
Now,
The magnification of the telescope will be:
⇒
⇒
⇒
I think it’s Energy is lost when machines don’t work right.
<span>59.027m/s^2
Centripetal force is give by F = mv^2/r
Since
F = ma
The acceleation accoiated with this centripetal force is
a=v^2/r
the radius is found by r=d/2=5.75m
velocity is found by
v=d/t
distance is the circumference of the circle
c=pi*d=11.5*3.14=36.11m
time=60s/30.6rpm=1.96s
v=36.11/1.96=18.423m/s
plugging this back in to
a=v^2/r=(18.423m/s)^2/5.75m=59.027m/s^2</span>
Answer:
So the car would skid 4 times the initial skidding displacement under the identical conditions when the car's initial velocity is just double.
Explanation:
Under identical conditions when the brakes are applied for the same body moving with twice the initial speed then we can analyse using the equation of motion.
Initially:
...........................(1)
where:
final velocity of the car = 0 (because the car stops)
initial velocity of the car
acceleration of the car (here it is deceleration and hence taken with negative sign)
displacement of the car before stopping
Final condition:
Initial velocity is,
So,
.............................(2)
Now divide eq. (2) by (1)
So the car would skid 4 times the initial skidding displacement under the identical conditions when the car's initial velocity is just double.