1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Svetach [21]
1 year ago
7

An RL series circuit is connected to an ac generator with a maximum emf of 20 V. If the maximum potential difference across the

resistor is 16 V, then the maximum potential difference across the inductor is:
Physics
1 answer:
Rama09 [41]1 year ago
5 0

If the maximum emf of the ac generator is 20 V and the maximum potential difference across the resistor is 16 V Then the maximum potential difference across the inductor is 4 V.

Calculation:

Step-1:

It is given that the RL circuit is connected to a 20 V ac generator. The maximum potential difference across the resistor is 16 V. It is required to find the maximum potential drop across the inductor.

Step-2:

The maximum emf of the generator is equal to the sum of the maximum potential difference across the resistor and the maximum potential difference across the inductor.

Therefore,

The maximum potential difference across the inductor + Maximum maximum potential difference across the resistor = Maximum emf of the generator

Thus,

Maximum maximum potential difference across the inductor + 16 V = 20 V

Therefore,

Maximum maximum potential difference across the inductor = 20 V - 16 V = 4 V

Learn more about potential differences across resistor and inductor here,

brainly.com/question/15715072

#SPJ4

You might be interested in
A factory worker pushes a crate of mass 31.0 kg a distance of 4.35 m along a level floor at constant velocity by pushing horizon
Debora [2.8K]

Answer:

a. 79.1 N

b. 344 J

c. 344 J

d. 0 J

e. 0 J

Explanation:

a. Since the crate has a constant velocity, its net force must be 0 according to Newton's 1st law. The push force F_p by the worker must be equal to the friction force F_f on the crate, which is the product of friction coefficient μ and normal force N:

Let g = 9.81 m/s2

F_p = F_f = \mu N = \mu mg = 0.26 * 31 * 9.81 = 79.1 N

b. The work is done on the crate by this force is the product of its force F_p and the distance traveled s = 4.35

W_p = F_ps = 79.1*4.35 = 344 J

c. The work is done on the crate by friction force is also the product of friction force and the distance traveled s = 4.35

W_f = F_fs = -79.1*4.35 = -344 J

This work is negative because the friction vector is in the opposite direction with the distance vector

d. As both the normal force and gravity are perpendicular to the distance vector, the work done by those forces is 0. In other words, these forces do not make any work.

e. The total work done on the crate would be sum of the work done by the pushing force and the work done by friction

W_p + W_f = 344 - 344 = 0 J

8 0
3 years ago
Read 2 more answers
2. Can the frictional force in this experiment be ignored? Explain.
neonofarm [45]

Answer:

i dont know

Explanation:

i dont know

5 0
2 years ago
A car travels 150 meters East of its original starting position in 15s. What is the cars velocity?​
Andrew [12]

Answer:

it is 347

Explanation:

6 0
2 years ago
Read 2 more answers
When heat flows from one substance to another, what happens to the temperature of the substance giving off the heat and to the t
blagie [28]
The temperature of the substance giving off the heat decreases while the temperature of the substance receilving the heat increases. they leach what is called equlibrium point where heat energy can longer be exchanged hence equql temperature. this isThermal physics
8 0
3 years ago
At a given instant the bottom A of the ladder has an acceleration aA = 4 f t/s2 and velocity vA = 6 f t/s, both acting to the le
Nana76 [90]

Answer:

Acceleration=24.9ft^2/s^2

Angular acceleration=1.47rads/s

Explanation:

Note before the ladder is inclined at 30° to the horizontal with a length of 16ft

Hence angular velocity = 6/8=0.75rad/s

acceleration Ab=Aa +(Ab/a)+(Ab/a)t

4+0.75^2*16+a*16

0=0.75^2*16cos30°-a*16sin30°---1

Ab=0+0.75^2sin30°+a*16cos30°----2

Solving equation 1

(0.75^2*16cos30/16sin30)=angular acceleration=a=1.47rad/s

Also from equation 2

Ab=0.75^2*16sin30+1.47*16cos30=24.9ft^2/s^2

6 0
3 years ago
Other questions:
  • Please help.
    14·2 answers
  • Two identical batteries, each with an emf of 18 V and an internal resistance of 1 :, are wired in parallel by connecting their p
    12·1 answer
  • What are the signs of "Depression"?
    12·2 answers
  • By applying the third law of motion, which force is greater when you push on a wall? Your force, the wall’s force, your force an
    5·2 answers
  • 2. In the pendulum lab, the period (swing time) was O a. the independent variable O b.graphed on the vertical-axis O c.graphed o
    8·1 answer
  • The AB rope is fixed to the ground at its A end, and forms 30º with the vertical. Its other end is connected to two ropes by mea
    11·1 answer
  • Q3. A man walks with a speed of 8 m/sec in 40 sec. How much distance was covered?
    10·2 answers
  • What energy does a spillway produce?​
    6·2 answers
  • 3. According to the article, why did Europeans so quickly accept that the sun did move and change?
    5·2 answers
  • Use heavy-duty grounded extension cords. Heavy-duty cords will have a marking on the insulation such as ___.
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!