1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
lora16 [44]
1 year ago
6

A thin flexible gold chain of uniform linear density has a mass of 17.1 g. It hangs between two 30.0 cm long vertical sticks (ve

rtical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale.
Evaluate the magnitude of the force on the left hand pole.

Physics
2 answers:
Elanso [62]1 year ago
6 0

The magnitude of the force on the left-hand pole of the thin flexible gold chain of uniform linear density with a mass of 17.1 and, hangs between two 30.0 cm long vertical sticks, which are a distance of 30.0 cm apart will be, 0.167N.

To find the correct answer, we have to know more about the Basic forces that acts upon a body.

<h3>What is force and which are the basic forces that acts upon a body?</h3>
  • A push or a pull which changes or tends to change the state or rest, or motion of a body is called Force.
  • Force is a polar vector as it has a point of application.
  • Positive force represents repulsion and the negative force represented attraction.
  • There are 3 main forces acting on a body, such as, weight mg, normal reaction N, and the Tension or pulling force.
<h3>How to solve the problem?</h3>
  • We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal distance between then is 30cm.
  • From the given data, we can find the angle  (in the free body diagram, it is given as θ).

                                    tan\alpha =\frac{30}{30}\\ \alpha =45^0

  • From the free body diagram given, we can write the balanced equations of total force along y direction as,

                                 y-direction\\T_2sin\alpha =mg\\\\T_2=\frac{mg}{sin\alpha } =\frac{17.1*10^{-3}*9.8}{sin45} \\\\T_2=0.236N

  • From the free body diagram given, we can write the balanced equations of total force along x direction as,

                                 x-direction\\T_1-T_2cos\alpha =0\\T_1=T_2cos\alpha \\T_1=0.236*cos45=0.167N

Thus, we can conclude that, the magnitude of force on the left-hand pole will be 0.167N.

Learn more about the Basic forces that acts upon a body here:

brainly.com/question/28106866

#SPJ1

grigory [225]1 year ago
3 0

The force acting on the left-hand pole of a thin, flexible gold chain of uniform linear density weighing 17.1 grams that is suspended between two vertical sticks that are 30.0 cm apart will be 0.167 N in magnitude.

We need to learn more about the fundamental forces that affect a body in order to arrive at the right answer.

<h3>What exactly is force, and what are the fundamental forces that affect a body?</h3>
  • Force is a push or a pull that modifies or tends to modify the condition, rest, or motion of a body.
  • Given that it has a point of application, force is a polar vector.
  • Repulsion is represented by positive force, and attraction by negative force.
  • A body is subject to three main forces: weight mg, normal response N, and tension or pulling force.
<h3>How can the issue be resolved?</h3>
  • We have given that, the gold chain hangs between the vertical sticks of 30cm and the horizontal space between then is 30cm.
  • We can determine the angle (shown as in the free body figure) using the information provided.

                              \alpha =tan^{-1}(\frac{30}{30})=45^0

  • We may get the balanced equations for the total force in the y direction from the provided free body diagram as follows:

                                T_2sin\alpha =mg\\T_2=\frac{mg}{sin\alpha } =0.236N

  • We can create the balanced equations for the total force in the x direction using the provided free body diagram:

                                     T_1=T_2cos\alpha \\T_1=0.167N

Thus, we may infer that the force acting on the left-hand pole will have a value of 0.167N.

Learn more about the Basic forces that acts upon a body here:

brainly.com/question/28106866

#SPJ1

You might be interested in
An airplane flies at 400 km/h in a 100km/h hurricane crosswind. Find the resultant speed of the plane.
kow [346]
I think the airplan flies in same speed 400
5 0
3 years ago
Sweating and panting are examples of which characteristics of life?
Marianna [84]
C.reproducing is think and if wrong I'm so very sorry
7 0
3 years ago
Read 2 more answers
A lady bug is sitting on the bottom of a can while you twirl it overhead on a string that is 65.0
MA_775_DIABLO [31]

The linear speed of the ladybug is 4.1 m/s

Explanation:

First of all, we need to find the angular speed of the lady bug. This is given by:

\omega=\frac{2\pi}{T}

where

T is the period of revolution

The period of revolution is the time taken by the ladybug to complete one revolution: in this case, since it does 1 revolution every second, the period is 1 second:

T = 1 s

Therefore, the angular speed is

\omega=\frac{2\pi}{1 s}=6.28 rad/s

Now we can find the linear speed of the ladybug, which is given by

v=\omega r

where:

\omega=6.28 rad/s is the angular speed

r = 65.0 cm = 0.65 m is the distance of the ladybug from the axis of rotation

Substituting, we find

v=(6.28)(0.65)=4.1 m/s

Learn more about angular speed:

brainly.com/question/9575487

brainly.com/question/9329700

brainly.com/question/2506028

#LearnwithBrainly

7 0
3 years ago
The ink drops have a mass m = 1.00×10^−11 kg each and leave the nozzle and travel horizontally toward the paper at velocity v =
luda_lava [24]

Answer:

9.98 × 10⁻⁹ C

Explanation:

mass, m = 1.00 × 10⁻¹¹ kg

Velocity, v = 23.0 m/s

Length of plates D₀ = 1.80 cm = 0.018 m

Magnitude of electric field, E = 8.20 × 10⁴ N/C

drop is to be deflected a distance d = 0.290 mm = 0.290 × 10⁻³ m

density of the ink drop = 1000 kg/m^3

Now,

Time = \frac{\textup{Distance}}{\textup{Velocity}}

or

Time = \frac{\textup{0.016}}{\textup{23}}

or

Time = 6.9 × 10⁻⁴ s

Now, force due to the electric field, F = q × E

where, q is the charge

Also, Force = Mass × acceleration

q × E = 1.00 × 10⁻¹¹ × a

or

a = \frac{q\times8.20\times10^4}{1\times10^{-11}}

Now from the Newton's equation of motion

d=ut+\frac{1}{2}at^2

where,  

d is the distance

u is the initial speed  

a is the acceleration

t is the time

or

0.290\times10^{-3}=0\times(6.9\times10^{-4})+\frac{1}{2}\times(\frac{q\times8.20\times10^4}{1\times10^{-11}})\times(6.9\times10^{-4})^2

or

q = 9.98 × 10⁻⁹ C

4 0
3 years ago
Consider a system to be two train cars traveling toward each other. What is the total momentum of the system before the train ca
Brut [27]

Let say the two train cars are of masses m_1 and m_2

now if the speed of two cars are v_1 and v_2

then we can say that the momentum of two cars before they collide is given by

P = m_1v_1 - m_2v_2

here two cars are moving in opposite direction so we can say that the net momentum is subtraction of two cars momentum.

Now since in these two car motion there is no external force on them while they collide

So the momentum of two cars are always conserved.

hence we can say that the final momentum of two cars will be same after collision as it is before collision

P = m_1v_1 - m_2v_2

5 0
3 years ago
Read 2 more answers
Other questions:
  • Please help only eight questions C:
    12·2 answers
  • Estimate how much power is saved if the voltage is stepped up from 150 VV to 1500 VV and then down again, rather than simply tra
    14·1 answer
  • Why does it hurt your hands when you carry heavy shopping in carrier bags?
    5·2 answers
  • A bowling ball is dropped from a height of 24 feet.
    15·1 answer
  • Which factors are involved in earthquakes formation (multiple choice)
    15·2 answers
  • Which trends is indirectly proportional to effective nuclear charge
    12·1 answer
  • Two speakers separated by a distance of 4.40 m emit sound. The speakers have opposite phase. A person listens from a location 3.
    15·1 answer
  • A wooden rod of negligible mass and length 80.0cm is pivoted about a horizontal axis through its center. A white rat with mass 0
    11·1 answer
  • Once the crate in sample problem 4C is in motion, a horizontal force of 53 N keeps the crate moving with a constant velocity. Fi
    14·2 answers
  • Compare the momentum of a 7160 kg truck moving at 5.00 m/s to the
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!