Ask question

Ask question

All categories

Irina-Kira [14]

2 years ago

13

NUMBER 8. NOWWWWWWWW

1 answer:

ss7ja [257]2 years ago

7 0

Torque = r x F

|F| = mg = 60 * 10 N = 600 N ( assuming g ~ 10m/s^2)

distance of fulcrum = torque / Force = 90/600 m = .15 m.

You might be interested in

PLEASE HELPPPPP!!!! :)

GuDViN [60]

Answer:

F=X.F=mxq. 3. 1 N/kg=0.5kg g=9.80

4 0

2 years ago

Which measurements are equal to 321 decimeters

vlabodo [156]

You are currently converting Distance and Length units from Centimeters to Feet 321 Centimeters (cm) = 10.5315 Feet (ft) This is a hard one but see if this helps if not let me now and i can try again..

7 0

3 years ago

A thermometer containing 0.10 g of mercury is cooled from 15 degrees celsius to 8.5 degrees celcius. How much energy left the me

loris [4]

To solve this exercise we will use the concept related to heat loss which is mathematically given as

$Q = mC_p \Delta T$

Where,

m = mass

$C_p$ = Specific Heat

$\Delta T =$ Change in temperature

Replacing with our values we have that

$m = 0.1g$

$C_p = 139J/Kg\cdot K \rightarrow$ Specific heat of mercury

$\Delta T = 8.5\°C-15\°C = -6.5\°C \Rightarrow -6.5K$

Replacing

$Q = (0.1*10^3)(138)(-6.5)\\Q = -0.09J$

Therefore the heat lost by mercury is 0.09J

5 0

3 years ago

The space shuttle is descending through the earth's atmosphere. How is the force of gravity affected?

polet [3.4K]

The answer would be C. It will decrease with descent. Hope this helps!

5 0

3 years ago

Read 2 more answers

Dave wishes to get produce from the store, which is a distance D- 2.2 km east of his house. Dave drives his bike to the store at

Neporo4naja [7]

Answer:

a) $t_1=338.4615\ s$

b) $t=1386.0805\ s$

c) $t=23.1013\ min$

d) $d=4400\ m$

e) Since Dave starts from house and finally returns to the house so displacement is zero.

Explanation:

Given:

distance between the house and the store, $s=2.2\ km=2200\ m$

speed of driving from house to store, $v_1=-6.5\ m.s^{-1}$

speed of driving back from store to house, $v_2=2.1\ m.s^{-1}$

Since the store is located towards east from his house and the velocity in this direction is taken negative and contrary to this the velocity in the west direction is taken positive.

a)

time taken in reaching the store:

$t_1=\frac{s}{v_1}$

$t_1=\frac{-2200}{-6.5}$

$t_1=338.4615\ s$

b)

Now the time taken in returning form the store:

$t_2=\frac{s}{v_2}$

$t_2=\frac{2200}{2.1}$

$t_2=1047.6190\ s$

therefore total time taken by the trip:

$t=t_1+t_2$

$t=338.4615+1047.6190$

$t=1386.0805\ s$

c)

the time taken by the trip in minutes:

$t=\frac{1386.0805}{60}$

$t=23.1013\ min$

d)

distance travelled in the whole trip:

$d=2\times s$

$d=2\times 2200$

$d=4400\ m$

e)

Since Dave starts from house and finally returns to the house so displacement is zero.

3 0

3 years ago