Assuming that there is in a vacuum, the two object will cool at the same rate, because the objects are made of the same material they will have the same cooling rate, assuming the surrounding temperature is the same.
Answer:
magnification will be -0.025
Explanation:
We have given the radius of curvature = 12 cm
And object distance = 3 m
So focal length 
Now for mirror we know that
So 

v = 0.750 m
Now magnification of the mirror is 
The approximate speed of the sound wave traveling through the solid material is 1012m/s.
<h3>
Wavelength, Frequency and Speed</h3>
Wavelength is simply the distance over which the shapes of waves are repeated. It is the spatial period of a periodic wave.
From the wavelength, frequency and speed relation,
λ = v ÷ f
Where λ is wavelength, v is velocity/speed and f is frequency.
Given the data in the question;
- Frequency of sound wave f = 440Hz = 440s⁻¹
- Wavelength of the wave λ = 2.3m
To determine the approximate speed of the wave, we substitute our given values into the expression above.
λ = v ÷ f
2.3m = v ÷ 440s⁻¹
v = 2.3m × 440s⁻¹
v = 1012ms⁻¹
v = 1012m/s
Therefore, the approximate speed of the sound wave traveling through the solid material is 1012m/s.
Learn more about Speed, Frequency and Wavelength here: brainly.com/question/27120701
Answer:
346.01 × 10² Lux
Explanation:
Given:
luminance of the sun at zenith at sea level, Ls = 1600 × 10 cd/m²
The diameter of the sun's photosphere = 8.64 × 10 miles = 45.62 × 10⁸ ft
or
Radius, r =
or
r = 22.81 × 10⁸ ft
The distance from the sun to the earth = 92.9 × 10 miles = 49.05 x 10¹⁰ ft
Now,
Lumen = Luminance × 4πr²
or
Lumen = 1600 × 10 cd/m² × 4πr² .....................(1)
also,
Illumination =
on substituting lumen from 1
Illumination =
or
Illumination =
or
Illumination = 346.01 × 10² Lux