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olganol [36]
3 years ago
6

An elephant lifts 7 large logs from the ground to a container 5 meters above the ground as part of a zoo demonstration. The elep

hant exerted a force of 250 Newtons to lift each log. How much work did the elephant do altogether? A. 1250 J B. 1750 J C. 7880 J D. 8750 J
Physics
1 answer:
Alisiya [41]3 years ago
5 0
The work done by the elephant to lift one log is the force multiplied by the height at which the log has been lifted:
W=Fh=250 N \cdot 5 m=1250 J
And so, the total work done to lift the 7 logs is 7 times the work done to lift each log:
W_t = 7 W=7 \cdot 1250 N=8750 J
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Answer:

mass = 0.18 [kg]

Explanation:

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mass = 0.18*1

mass = 0.18 [kg]

6 0
3 years ago
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1. 343m/s / 0.77955m = 439.99 Hz   
     This corresponds to pitch A 

2. 343m/s / 0.52028m = 659.26 Hz
</span>     This corresponds to pitch E 
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3. 343m/s / 0.65552m = 523.349 Hz
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4. using f = c /  λ
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3 0
3 years ago
For a centrifugal compressor, the flow at the exit of the blade (state 2) has a velocity of 250 m/s with an angle of 15 degrees
shtirl [24]

The velocity at the end of vaneless space(state 3) is  965.92 m/s

<h3>What is centrifugal compressor?</h3>

It increases kinetic energy to the airstream using a rotating element and then converts it into potential energy in the form of pressure.

Temperature at state 2, T₂ =T₀ + c/2Cp

Substitute T₀ =450K, c=250m/s, Cp =1005, we get

T₂ =418.90K

From the velocity triangle, sinβ₂ =c₂/v₂

v₂ = 250/sin (90°-75°) = 965.92 m/s

Thus, the velocity at the end of vaneless space is 965.92 m/s.

Learn more about centrifugal compressor.

brainly.com/question/9131351

#SPJ4

6 0
3 years ago
In the carbon cycle, carbon is transferred from animals to decomposers in all of the following ways EXCEPT
Ad libitum [116K]
Hello.

The answer is <span>C) as carbon dioxide.

Have  a nice day </span>
7 0
3 years ago
Read 2 more answers
An RV is traveling 60 km/h along a highway. A boy sitting near the driver of the RV throws a ball to another boy at the back end
alina1380 [7]

Answer:

Speed of the ball relative to the boys: 25 km/h

Speed of the ball relative to a stationary observer: 35 km/h

Explanation:

The RV is travelling at a velocity of

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Here we have taken the direction of motion of the RV as positive direction.

The boy sitting near the driver throws the ball back with speed of 25 km/h, so the velocity of the ball in the reference frame of the RV is

v_B = -25 km/h

with negative sign since it is travelling in the opposite direction relative to the RV. Therefore, this is the velocity measured by every observer in the reference frame of the RV: so the speed measured by the boys is

v = 25 km/h

Instead, a stationary observer outside the RV measures a velocity of the ball given by the algebraic sum of the two velocities:

v = +60 km/h + (-25 km/h) = +35 km/h

So, he/she measures a speed of 35 km/h.

5 0
3 years ago
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