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svp [43]
3 years ago
12

Label the eurkaryotic cell​

Chemistry
1 answer:
Scilla [17]3 years ago
7 0

Answer:

Here's your label diagram!

Explanation:

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Consider the following representation of a reaction mechanism.
Stells [14]

The rate law depends on only A because it is the reactant in the rate-determining step.

<h3>What is the rate law;</h3>

The rate law is a representation of the rate of reaction. The fast reaction is  E+B ------> A+ D. The slow reaction is A + A ----->C + E. The overall reaction is A + B ------> C + D.

We know that the rate law depends  only on the  the slow reaction hence the rate law depends on only A because it is the reactant in the rate-determining step.

Learn more about the rate law:brainly.com/question/4222261

#SPJ1

4 0
2 years ago
What kind of chemical bonds are represented by the product in the following diagram?
katovenus [111]
The chemical bonds in CH4 are all single bonds. C only can bond 4 times because it needs 8 electrons in it's outer shell and only has four right now. The bonds represented are all single bonds because there are two electrons present on each side of the carbon. Two electrons, in this case, equals one bond.
4 0
3 years ago
Which of the following is a chemical change?
FromTheMoon [43]

<u>Answer:</u>

<em>Silver tarnishing as the silver metal reacts with sulphur is a chemical change.</em>

<u>Explanation:</u>

Tarnishing is the process of chemical change occurring on the surface of objects leading to corrosion or other defects on the surface. The remaining options like dilution, eroding is a physical change where the concentration of salt and rock particles will be decreased, respectively.

Similarly for soil drying also the concentration of water will be decreased leading to a physical change from wetty or dry soil.

But the last option which indicates tarnishing of silver metal on reaction with sulphur is a chemical process as the surface of silver metal will be reacting to sulphur and leads to lose of electrons which leads to corrosion of the surface or tarnishing of silver.

4 0
3 years ago
Read 2 more answers
What’s the answers to these?
nata0808 [166]

Answer:

0bervation

Explanation:

cause it is

5 0
3 years ago
Will a precipitate of magnesium fluoride form when 300. mL of 1.1 × 10 –3 M MgCl 2 are added to 500. mL of 1.2 × 10 –3 M NaF? [K
Tju [1.3M]

Answer:

No precipitate is formed.

Explanation:

Hello,

In this case, given the dissociation reaction of magnesium fluoride:

MgF_2(s)\rightleftharpoons Mg^{2+}+2F^-

And the undergoing chemical reaction:

MgCl_2+2NaF\rightarrow MgF_2+2NaCl

We need to compute the yielded moles of magnesium fluoride, but first we need to identify the limiting reactant for which we compute the available moles of magnesium chloride:

n_{MgCl_2}=0.3L*1.1x10^{-3}mol/L=3.3x10^{-4}molMgCl_2

Next, the moles of magnesium chloride consumed by the sodium fluoride:

n_{MgCl_2}^{consumed}=0.5L*1.2x10^{-3}molNaF/L*\frac{1molCaCl_2}{2molNaF} =3x10^{-4}molMgCl_2

Thus, less moles are consumed by the NaF, for which the moles of formed magnesium fluoride are:

n_{MgF_2}=3x10^{-4}molMgCl_2*\frac{1molMgF_2}{1molMgCl_2}=3x10^{-4}molMgF_2

Next, since the magnesium fluoride to magnesium and fluoride ions is in a 1:1 and 1:2 molar ratio, the concentrations of such ions are:

[Mg^{2+}]=\frac{3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =3.75x10^{-4}M

[F^-]=\frac{2*3x10^{-4}molMg^{+2}}{(0.3+0.5)L} =7.5x10^{-4}M

Thereby, the reaction quotient is:

Q=(3.75x10^{-4})(7.5x10^{-4})^2=2.11x10^{-10}

In such a way, since Q<Ksp we say that the ions tend to be formed, so no precipitate is formed.

Regards.

6 0
3 years ago
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