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taurus [48]
2 years ago
10

In order for a gear to work in a piece of machinery, the radius of the gear, r, must be greater than 4 cm, but not exceed 4.1 cm

. Which compound inequality represents the situation?
r > 4 and r ≤ 4.1
r > 4 or r ≤ 4.1
r < 4 and r ≥ 4.1
r < 4 or r ≥ 4.1
Mathematics
1 answer:
sveta [45]2 years ago
6 0

The compound inequality represents the situation is r > 4 and r ≤ 4.1

<h3>Compound inequality</h3><h3 />
  • Radius of the gear = r

  • r must be greater than 4 cm

r > 4

  • r must not exceed 4.1 cm

r ≤ 4.1

Therefore, r > 4 and r ≤ 4.1 is the compound inequality which represent the situation.

Learn more about compound inequality:

brainly.com/question/234674

#SPJ1

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What is the equation for the plane illustrated below?
TiliK225 [7]

Answer:

Hence, none of the options presented are valid. The plane is represented by 3 \cdot x + 3\cdot y + 2\cdot z = 6.

Step-by-step explanation:

The general equation in rectangular form for a 3-dimension plane is represented by:

a\cdot x + b\cdot y + c\cdot z = d

Where:

x, y, z - Orthogonal inputs.

a, b, c, d - Plane constants.

The plane presented in the figure contains the following three points: (2, 0, 0),  (0, 2, 0), (0, 0, 3)

For the determination of the resultant equation, three equations of line in three distinct planes orthogonal to each other. That is, expressions for the xy, yz and xz-planes with the resource of the general equation of the line:

xy-plane (2, 0, 0) and (0, 2, 0)

y = m\cdot x + b

m = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

Where:

m - Slope, dimensionless.

x_{1}, x_{2} - Initial and final values for the independent variable, dimensionless.

y_{1}, y_{2} - Initial and final values for the dependent variable, dimensionless.

b - x-Intercept, dimensionless.

If x_{1} = 2, y_{1} = 0, x_{2} = 0 and y_{2} = 2, then:

Slope

m = \frac{2-0}{0-2}

m = -1

x-Intercept

b = y_{1} - m\cdot x_{1}

b = 0 -(-1)\cdot (2)

b = 2

The equation of the line in the xy-plane is y = -x+2 or x + y = 2, which is equivalent to 3\cdot x + 3\cdot y = 6.

yz-plane (0, 2, 0) and (0, 0, 3)

z = m\cdot y + b

m = \frac{z_{2}-z_{1}}{y_{2}-y_{1}}

Where:

m - Slope, dimensionless.

y_{1}, y_{2} - Initial and final values for the independent variable, dimensionless.

z_{1}, z_{2} - Initial and final values for the dependent variable, dimensionless.

b - y-Intercept, dimensionless.

If y_{1} = 2, z_{1} = 0, y_{2} = 0 and z_{2} = 3, then:

Slope

m = \frac{3-0}{0-2}

m = -\frac{3}{2}

y-Intercept

b = z_{1} - m\cdot y_{1}

b = 0 -\left(-\frac{3}{2} \right)\cdot (2)

b = 3

The equation of the line in the yz-plane is z = -\frac{3}{2}\cdot y+3 or 3\cdot y + 2\cdot z = 6.

xz-plane (2, 0, 0) and (0, 0, 3)

z = m\cdot x + b

m = \frac{z_{2}-z_{1}}{x_{2}-x_{1}}

Where:

m - Slope, dimensionless.

x_{1}, x_{2} - Initial and final values for the independent variable, dimensionless.

z_{1}, z_{2} - Initial and final values for the dependent variable, dimensionless.

b - z-Intercept, dimensionless.

If x_{1} = 2, z_{1} = 0, x_{2} = 0 and z_{2} = 3, then:

Slope

m = \frac{3-0}{0-2}

m = -\frac{3}{2}

x-Intercept

b = z_{1} - m\cdot x_{1}

b = 0 -\left(-\frac{3}{2} \right)\cdot (2)

b = 3

The equation of the line in the xz-plane is z = -\frac{3}{2}\cdot x+3 or 3\cdot x + 2\cdot z = 6

After comparing each equation of the line to the definition of the equation of the plane, the following coefficients are obtained:

a = 3, b = 3, c = 2, d = 6

Hence, none of the options presented are valid. The plane is represented by 3 \cdot x + 3\cdot y + 2\cdot z = 6.

8 0
3 years ago
Do 8feet + 10feet + 12feet make a right triangle
bija089 [108]

9514 1404 393

Answer:

 no

Step-by-step explanation:

If triangle side lengths are an arithmetic sequence (have a common difference), they must have the ratios 3:4:5 to make a right triangle. Here, the ratios of the side lengths are 4:5:6, so will not be a right triangle.

4 0
3 years ago
.98*125<br> 13.75*12<br> 143.43/31
vova2212 [387]

Answer:

n = 6

n, = 6n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2n = 6

n, = 6

n = 0

n, = 0

n = 4

n, = 4

n = 2

n, = 2

'

3 0
3 years ago
6. a semicircle has as its diameter the hypotenuse of a right triangle shown below. determine the area of the semicircle to the
jeyben [28]

Answer:

A = 137.3cm^2

Step-by-step explanation:

Given

See attachment

Required

The area of the semicircle

First, we calculate the hypotenuse (h) of the triangle

Considering only the triangle, we have:

\cos(68) = \frac{7}{h} --- cosine formula

Make h the subject

h = \frac{7}{\cos(68)}

h = \frac{7}{0.3746}

h = 18.7

The area of the semicircle is then calculated as:

A = \frac{\pi h^2}{8}

This gives:

A = \frac{3.14 * 18.7^2}{8}

A = \frac{1098.03}{8}

A = 137.3cm^2

7 0
3 years ago
ABCD=STQR. What is CD?
ololo11 [35]

Answer:

CD = QR because abcd= star then last 2 are answer

8 0
2 years ago
Read 2 more answers
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