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kramer
2 years ago
15

Show that the relationship between impulse and the change in momentum is another way of staying Newton’s second law of motion

Physics
1 answer:
Hitman42 [59]2 years ago
5 0

The impulse-momentum theorem states that the rate of change of momentum of an object is equal to the impulse applied to it. This is logically equal to Newton's second law of motion.

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A ball is projected with an initial velocity of 40 meter per second and reached maximum height of 160 meters calculate tge angle
Andru [333]

There's a problem with the question as given. Even with a maximum projection angle of <em>θ</em> = 90°, the initial velocity is not large enough to get the ball up in the air 160 m. With angle 90°, the ball's height <em>y</em> at time <em>t</em> would be

<em>y</em> = (40 m/s) <em>t</em> - 1/2 <em>g t</em> ²

Set <em>y</em> = 160 m, and you'll find that there is no (real) solution for<em> t</em>, so the ball never attains the given maximum height.

From another perspective: recall that

<em>v </em>² - <em>v</em>₀² = 2<em>a </em>∆<em>y</em>

where

• <em>v</em>₀ = initial velocity

• <em>v</em> = final velocity

• <em>a</em> = acceleration

• ∆<em>y</em> = displacement

At its maximum height, the ball has zero vertical velocity, and ∆<em>y</em> = maximum height = 160 m. The ball is in free fall once it's launched, so <em>a</em> = -<em>g</em>.

So we have

0² - (40 m/s)² = -2<em>g </em>(160 m)

but this reduces to

(40 m/s)² = 2 (9.8 m/s²) (160 m)

1600 m²/s² ≠ 3136 m²/s²

7 0
3 years ago
A skater of mass 60 kg has an initial velocity of 12 m/s. He slides on ice where the frictional force is 36 N. How far will the
Alexus [3.1K]

Answer:

d = 120 [m]

Explanation:

In order to solve this problem, we must use the theorem of work and energy conservation. Where the energy in the final state (when the skater stops) is equal to the sum of the mechanical energy in the initial state plus the work done on the skater in the initial state.

The mechanical energy is equal to the sum of the potential energy plus the kinetic energy.  As the track is horizontal there is no unevenness, in this way, there is no potential energy.

E₁ + W₁₋₂ = E₂

where:

E₁  = mechanical energy in the initial state [J] (units of Joules)

W₁₋₂ = work done between the states 1 and 2 [J]

E₂  = mechanical energy in the final state = 0

E₁ = Ek = kinetic energy [J]

E₁ = 0.5*m*v²

where:

m = mass = 60 [kg]

v = initial velocity = 12 [m/s]

Now, the work done is given by the product of the friction force by the distance. In this case, the work is negative because the friction force is acting in opposite direction to the movement of the skater.

W₁₋₂ = -f*d

where:

f = friction force = 36 [N]

d = distance [m]

Now we have:

0.5*m*v² - (f*d) = 0

0.5*60*(12)² - (36*d) = 0

4320 = 36*d

d = 120 [m]

7 0
3 years ago
The critical angle in air for a particular type of glass is 39.0°. What is the speed of light in this class glass? (c = 3.00 × 1
hodyreva [135]

Answer:

speed of light in glass ≈ 1.89*10^{8}m/s

Explanation:

refractive index (n) =\frac{1}{sinC}            .......................equation 1

refractive index (n) = velocity of light in air/ velocity of light in medium  ....equ2

equate equation 1 and two;

\frac{1}{sinC} = \frac{c}{speed of light in glass}

speed of light in glass = c*sinC

                            =3*10^{8}*sin39°

speed of light in glass = 188,796,117.314 m/s

speed of light in glass ≈ 1.89*10^{8}m/s

7 0
3 years ago
The moon does not stay at the same distance from the earth.why?​
Artist 52 [7]

Answer:

The moon does not stay at the same distance of the earth because the ortbit of the moon is slightly elliptical. If earth is not tilted at an angle of 66.5°, there will be no change in the season and the earth will have equal length of days and night.

Explanation:

mark me brainlest

5 0
3 years ago
A boy throws a water balloon at his friend. If the work done on the balloon is 20j and it has a mass of 1kg what is the speed of
inessss [21]

Answer:

The speed of of the balloon is about 6.32 m/s

Explanation:

Assuming all of the work done is transformed into the balloon's kinetic energy, we can use the formula for the kinetic energy to answer the question:

E_k=\frac{1}{2}mv^2\\20J = \frac{1}{2}1kg\cdot v^2\implies v=\pm\sqrt{40\frac{m^2}{s^2}}\approx\pm6.32\frac{m}{s}

Speed is the absolute value of velocity, so the speed of the balloon is about 6.32 m/s

7 0
3 years ago
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