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Harrizon [31]
3 years ago
10

A boy throws a water balloon at his friend. If the work done on the balloon is 20j and it has a mass of 1kg what is the speed of

the balloon
Physics
1 answer:
inessss [21]3 years ago
7 0

Answer:

The speed of of the balloon is about 6.32 m/s

Explanation:

Assuming all of the work done is transformed into the balloon's kinetic energy, we can use the formula for the kinetic energy to answer the question:

E_k=\frac{1}{2}mv^2\\20J = \frac{1}{2}1kg\cdot v^2\implies v=\pm\sqrt{40\frac{m^2}{s^2}}\approx\pm6.32\frac{m}{s}

Speed is the absolute value of velocity, so the speed of the balloon is about 6.32 m/s

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Claire just purchased a new silk dress for her school’s winter formal. She loves the feel of silk and keeps rubbing it with her
bezimeni [28]

Answer:

C.

would adapt if the dress were held completely still

Explanation:

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3 years ago
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A power plant produces 1000 MW to suply a city 40Km away.Current flows from the power plant on a single wire of resistance0.050
Westkost [7]

Answer:

The current in wire resistance 2Ω

a). 8696 A

b). fraction power 15.1% a 115kV

Explanation:

Resistance

R=0.05Ω/Km*40km

R=2Ω

P=1000 MW

a).

P=V*I\\I=\frac{P}{V}=\frac{1000x10^{6}W}{115x10^{3}k }  =8696.65A

Using law ohm

b).

V=I*R\\I=\frac{V}{R}

P=I*I*R\\P=I^{2} *R\\P=8696.65^{2}*2\\P=151.228 x10^{6}  W

e=\frac{151.228x10^{6} }{1000x10^{6} }*100= 15.12%

8 0
3 years ago
Consider the hydrogen atom. How does the energy difference between adjacent orbit radii change as the principal quantum number i
Kisachek [45]

Answer:

the energy difference between adjacent levels decreases as the quantum number increases

Explanation:

The energy levels of the hydrogen atom are given by the following formula:

E=-E_0 \frac{1}{n^2}

where

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n is the level number

We can write therefore the energy difference between adjacent levels as

\Delta E=-13.6 eV (\frac{1}{n^2}-\frac{1}{(n+1)^2})

We see that this difference decreases as the level number (n) increases. For example, the difference between the levels n=1 and n=2 is

\Delta E=-13.6 eV(\frac{1}{1^2}-\frac{1}{2^2})=-13.6 eV(1-\frac{1}{4})=-13.6 eV(\frac{3}{4})=-10.2 eV

While the difference between the levels n=2 and n=3 is

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And so on.

So, the energy difference between adjacent levels decreases as the quantum number increases.

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3 years ago
A white dwarf star has a density of about 1.0 x 10^9 kg/m3. If the earth were to suddenly become as dense as a white dwarf star,
GalinKa [24]

Answer:

R = 98304.75 m = 98.3 km

Explanation:

The density of an object is given as the ratio between the mass of that object and the volume occupied by that object.

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Now, it is given that the density of Earth has become:

Density = 1 x 10⁹ kg/m³

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R = Radius of Earth = ?

Therefore,

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<u>R = 98304.75 m = 98.3 km</u>

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