A student is given a box containing ten similar plastic drinking straws, a 30 cm ruler and two set-squares. (a) Explain how the
1 answer:
The way to perform the experiment is illustrated below.
<h3>How to perform the experiment?</h3>Place each straw tightly without deforming the roundness of the straw into the corner of the set square.
Measure the distance from the corner of the set square to where the straw touches the set square using the 30 cm ruler. This will be the radius of each straw.
Multiply this radius by 2 in order to obtain the diameter of each straw.
Sum the diameter of each of the 10 straws.
Divide this sum by 10 to obtain the average value for the diameter of a straw.
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Answer and Explanation:
Data provided in the question
Carbon mass = m
Initial speed = v_i
Coefficient = μk
Based on the above information, the expressions are as follows
a. By using the energy considerations the expression for the carton moving distance is
As we know that
where,
b. The initial speed of the carton if the factor of 3 risen, so the expression is
Answer:
The angle for the forward Mach line is 19.47°
The angle for the rearward Mach line is 5.21°
Explanation:
From table A-1 (Modern Compressible Flow: with historical perspective):
(M₁ = 3)
If Po₁ = Po₂
Table A-1:
Table A-5:
v₁ = 49.76°
μ₁ = 19.47°
v₂ = 60.55°
μ₂ = 16°
θ = 60.55 - 49.76 = 10.79°
The angle for the forward Mach line is:
μ₁ = 19.47°
The angle for the rearward Mach line is:
θr = μ₂ - θ = 16 - 10.79 = 5.21°
Answer:
the horizontal distance covered by the cannonball before it hits the ground is 327.5 m
Explanation:
Given;
height of the cliff, h = 210 m
initial horizontal velocity of the cannonball, Ux = 50 m/s
initial vertical velocity of the cannonball, Uy = 0
The time for the cannonball to reach the ground is calculated as;
The horizontal distance covered by the cannonball before it hits the ground is calculated as;
Therefore, the horizontal distance covered by the cannonball before it hits the ground is 327.5 m