Which of the following types of radiation can penetrate through paper but not through wood?

Physics

2 answers:

irina [24]4 years ago

7 0

Answer:

Beta rays

Explanation:

as we know that as per energy we can say that maximum energy is for gamma rays and minimum energy is for alpha rays

so here alpha rays are of least energy and it can not penetrate through the paper

while gamma rays are of maximum energy which is due to transitions in nuclear level so it can penetrate through any thickness

So here we have to choose which can penetrate through paper but can not penetrate through wood

so it is of moderate energy

So this must be Beta rays

andrew-mc [135]4 years ago

4 0

The type of radiation that can penetrate through paper, but not through wood is called beta rays. Beta rays can penetrate paper and air, but a thin piece of alimony can stop it. Gamma can cut through anything except lead and many inches of concrete. Alpha can be stopped by paper and not penetrated. The correct answer is B.

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Un tractor halando un carretón cargado con caña de azucar, viaja por el camino recto de una finca a una velocidad de 20 km/h. Si

Sidana [21]

Translation

A tractor pulling a cart loaded with sugar cane travels down the straight path of a farm at a speed of 20 km / h. If at 3:00 p.m.you pass the Finca Las Margaritas, what time will you arrive at the Las Ilusiones farm, located on the same road, if the distance between the two farms is 60 km

Answer:

6.00 pm

Explanation:

Speed is given by dividing distance by time and expressed as s=d/t. Making time the subject of the formula then t=d/s where s is the speed, d is distance covered and t is the time taken. Substituting 20 km/h for s and 60 km for d then t=60/20=3 hours

Adding 3 hours to 3 pm we get 6pm

Therefore, the time to reach the destination if the speed is constantly maintained is 6.00 pm

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3 years ago

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ICE Princess25 [194]

(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))

For (b): Use the formula for distance (s) made during an accelerated motion:

$s = \frac{1}{2}at^2+ v_0t+s_0= \frac{1}{2}at^2= \frac{1}{2}gt^2$

with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case solely due to gravitational acceleration so: "g."

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4 years ago

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sveta [45]

Answer:

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Explanation: