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Ronch [10]
3 years ago
15

What is the refractive index of air if light travels through it at 3.0 108 m/s?

Physics
1 answer:
olchik [2.2K]3 years ago
4 0

Answer:

n = c/v = (3.00 x 108 m/s)/(2.76 x 108 m/s) = 1.09. This does not equal any of the indices of refraction listed in the table.

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A sample of iron has the dimesions of 2 cm x 3cm x 2cm. If the mass of this rectangular-shaped object is 94g, what is the densit
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In fission processes, which of the following statements is true? The total number of protons and the total number of neutrons bo
Amiraneli [1.4K]

Answer: A. The total number of protons and the total number of neutrons both remain the same.

Explanation:

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7 0
3 years ago
Two boxers are fighting. Boxer 1 throws his 5 kg fist at boxer 2 with a speed of 9 m/s.
Sladkaya [172]

Answer:

0.001 s

Explanation:

The force applied on an object is equal to the rate of change of momentum of the object:

F=\frac{\Delta p}{\Delta t}

where

F is the force applied

\Delta p is the change in momentum

\Delta t is the time interval

The change in momentum can be written as

\Delta p=m(v-u)

where

m is the mass

v is the final velocity

u is the initial velocity

So the original equation can be written as

F=\frac{m(v-u)}{\Delta t}

In this problem:

m = 5 kg is the mass of the fist

u = 9 m/s is the initial velocity

v = 0 is the final velocity

F = -45,000 N is the force applied (negative because its direction is opposite to the motion)

Therefore, we can re-arrange the equation to solve for the time:

\Delta t=\frac{m(v-u)}{F}=\frac{(5)(0-9)}{-45,000}=0.001 s

4 0
3 years ago
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