W=20 e(-kt)
A. Rearranging gives k= -(ln(w/20)/t
Substituting w= 10 and solving gives k=0.014
B. Using W=20e(-kt). After 0 hours, W=20. After 24 hours, W=14.29g. After 1 week (24x7=168h) W=1.9g
C. Rearranging gives t=-(ln(10/20)/k. Substituting w=1 and solving gives t=214 hours.
D. Differentiating gives dW/ dt = -20ke(-kt). Solving for t=100 gives dW/dt = 0.07g/h. Solving for t=1000 gives 0.0000002g/h
E. dW/dt = -20ke(-kt). But W=20e(-kt) so dW/dt = -kW
Answer:
60 N.C
Explanation:
The box will move in the direction of the push and pull with a force of 60 N. C.
Answer:
The pressure at this depth is 
.
Explanation:
According to the statement, the uncompressed fluid stands at atmospheric pressure. By Boyle's Law we have the following expression:
(1)
Where:
- Initial and final volume.
- Initial and final pressure.
If we know that 
, then the pressure ratio is:
If 
, then the final pressure of the gas is:
The pressure at this depth is .
