All categories

4 years ago

2x(squared) + 23x-19=0

1 answer:

7 0

Use quadratic formula

for ax^2+bx+c=0
x= $\frac{-b+/- \sqrt{b^2-4ac} }{2a}$

given
2x^2+23x-19=0
a=2
b=23
c=-19

x= $\frac{-23+/- \sqrt{23^2-4(2)(-19)} }{2(2)}$
x= $\frac{-23+/- \sqrt{529-152} }{4}$
x= $\frac{-23+/- \sqrt{377} }{4}$

x= $\frac{-23+ \sqrt{377} }{4}$ or $\frac{-23- \sqrt{377} }{4}$

You might be interested in

Elena has $0.90. Kia has 10 times as much money

Vlada [557]

Answer:

Kia has ten times more money than Elena. Kia has more money that Elena.

Troy has one-tenth of the money Elena has. Troy has less money than Elena.

Step-by-step explanation:

3 0

3 years ago

Do this and I’ll pay u I need help

frutty [35]

Answer:

"bring me my money"

Step-by-step explanation:

8 0

3 years ago

1. Suppose that a theater charges a school group $4.50 per student to show a special film. Suppose that the theater's operating

elixir [45]

The functions I(x) and E(x) of the theatre's income and expenses are illustrations of linear functions.

<h3>The equation of the theatre's income</h3>

The theatre charges $4.50 per student.

Assume the number of students is x, the equation of the theatre's income would be:

I(x) = 4.5x

<h3>The equation of the theatre's expenses</h3>

The theatre expense per student is $1.25, and the operating cost on the staff is $130

The equation of the theatre's expenses would be:

E(x) = 1.25x + 130

<h3>Complete the table</h3>

Using the formulas I(x) = 4.5x and E(x) = 1.25x + 130, the complete table is:

Students, x 0 10 20 30 40 50 60 70

Income, I 0 45 90 135 180 225 270 315

Expenses, E 130 142.5 155 167.5 180 192.5 205 217.5

<h3>The graph of the theatre's income and expenses</h3>

See attachment

<h3>The pattern by which theatre's income and expenses increase</h3>

The functions I(x) and E(x) are linear functions.

So, the pattern with which the functions increase is a linear pattern.

<h3>The number of students when the theatre's income and expenses are equal</h3>

This means that:

I(x) = E(x)

So, we have:

4.5x = 1.25x + 130

Subtract 1.25 from both sides

3.25x = 130

Divide both sides by 3.25

x = 40

Hence, the number of students is 40

<h3>The theatre profit</h3>

This is the difference between the theatre expenses and their income.

So, we have:

P(x) = E(x) - I(x)

This gives

P(x) = 1.25x + 130 - 4.5x

Simplify

P(x) = 130 - 3.25x

<h3>Solution to the inequalities</h3>

We have:

E(x) < 255

This gives

1.25x + 130 < 255

Subtract 130 from both sides and divide by 1.25

x < 100 students

Also, we have:

I(x) > 675

This gives

4.5x > 657

Solve for x

x > 146 students

Hence, the number of students for the inequalities are less than 100 and greater than 146

Read more about linear equations and inequalities at:

brainly.com/question/11234618

8 0

2 years ago

Teresa is building a scale model of the JP Morgan chase Tower in Houston.In her scale model, 1.5 inches represents 61 meters. Si

Jet001 [13]

Answer:

Teresa should build 7.5 inches model.

Step-by-step explanation:

Consider the provided information.

Teresa is building a scale model of the JP Morgan chase Tower in Houston.

Her scale model, 1.5 inches represents 61 meters.

The actual building is 305 meters tall,

First find how many 61's are there in 305.

For this divide 305 by 61.

$\frac{305}{61}= 5$

Actual building is 5 times taller than 61. Thus the model should be 5 times taller than 1.5.

multiply 1.5 with 5 gives us:

$1.5\times 5=7.5$

Hence, Teresa should build 7.5 inches model.

7 0

3 years ago

At the movie theatre, child admission is $6.40 and adult admission is $9.90. On Friday, 154 tickets were sold for a total sales

Minchanka [31]

6.40x+9.90(154-x)=1230.90
Solve for x
X=84 for child

154-84=70 for adults

4 0

3 years ago