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2 years ago

I need help with constat rate of change please

Mathematics

1 answer:

Anit [1.1K]2 years ago

6 0

It’s 40 that’s the constant change of rate

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4 1/6 divided by 1 1/3

Zolol [24]

Answer:

$\frac{25}{8}$

Step-by-step explanation:

A fraction is a part of a whole .

A proper fraction is a fraction whose numerator is less than denominator .

For example $\frac{2}{3}\,,\,\frac{3}{4}$

An improper fraction is a fraction whose numerator is greater than denominator .

For example $\frac{5}{4}\,,\,\frac{8}{7}$

A mixed fraction is made up of whole number and a proper fraction .

Given : $4\frac{1}{6}\,,1\frac{1}{3}$

Solution :

$4\frac{1}{6}=\frac{4\times 6+1}{6}=\frac{25}{6}\\1\frac{1}{3}=\frac{3\times 1+1}{3}=\frac{4}{3}$

We need to divide $4\frac{1}{6}$ by $1\frac{1}{3}$ .

$4\frac{1}{6}\div 1\frac{1}{3}=\frac{25}{6}\div\frac{4}{3} \\\Rightarrow 4\frac{1}{6}\div 1\frac{1}{3}= \frac{25}{6}\times \frac{3}{4}=\frac{25}{8}$

3 0

3 years ago

What do we call the financial assistance that a student receives to pay for college that must be repaid, with interest, that add

Reil [10]

Its a loan , because its money u get from the bank and over time the interest adds up which u must pay back.

7 0

3 years ago

How do I simplify this?

liraira [26]

Step-by-step explanation:

The given question is wrong, so first of all we have correct this one.

The answer is given in picture, u can look.

I think this one is help u

4 0

3 years ago

Substitute the given values into the formula and solve for the unknown variable. If necessary, round to one decimal place

Stells [14]

Answer:

4=H

Step-by-step explanation:

H is unknown

180=4x7x5+2x5xH

180=140+10H

40=10H

4=H

7 0

3 years ago

Please help freshman math much-needed

Damm [24]

You can make the equatin: y=15x+22
X is the number of weeks
Y is the total amount of money needed

Plug in 120 for y and solve for x
120=15x+22
98=15x
x=6.53

But the answer is 7 weeks because we have to round up so he gets paid for the whole week

5 0

3 years ago

Read 2 more answers

I need help with constat rate of change please​

I need help with constat rate of change please