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alexira [117]
2 years ago
11

Use Hooke's Law to determine the variable force in the spring problem. A force of 7 pounds compresses a 15-inch spring a total o

f 3 inches. How much work is done in compressing the spring 7 inches
Physics
1 answer:
Harman [31]2 years ago
7 0

Work done in compressing spring =  40.833


It simply needs a three-inch compression by applying a compressive force to a 15-inch long spring. we know that  F(x)=kx. To act in displacement X and the poles' values cannot be substituted. Consequently, there will be 4. The spring constant K is therefore equal to 5, so. Three fit within this slot. We consequently derive the compressing spring constant K from this. , which is 5, 3. Now change this formula to include the value of the compressing spring constant. Four f will therefore equal 5.3 x and vice versa. Integration of four factors equals W.

In order to ensure the limit and further all of this, we currently have the range 0–7. Thus, this compressing spring task is completed. W is equal to  40.833

To learn more about Compressing spring please visit
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When heat is removed from a substance , describe how the molecules are affected
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I believe they would electron rate would slow down and the molecules would shrink.

I am almost positive that this is correct. I hope it helps!

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zubka84 [21]

Answer:

30%

Explanation:

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3 years ago
What is 34 + (5) × (1.2465) written with the correct number of significant figures?
bonufazy [111]

Answer: 40

Explanation:

= 34 + 5 * 1.2465

= ‭40.2325‬

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3 years ago
Two trains start a journey at the same time 120 miles apart, travelling towards each other. The first train is travelling at 60
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3 years ago
(a) What is the current involved when a truck battery sets in motion 720 C of charge in 4.00 s while starting an engine? (b) How
OLEGan [10]

Answer:

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(b) Time taken in calculator is 333.33 s

Explanation:

(a) Given:

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The relation between current, charge and time is:

I = q/t

Substitute the suitable values in the above equation.

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(b) Given:

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The relation between current, charge and time is:

t = q/I

Substitute the suitable values in the above equation.

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8 0
4 years ago
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