Answer:
v = 22.54 mph.
Explanation:
Given that,
Distance moved, d = 200 m
Time, t = 19.8 s
We need to find the runner's average speed.
We know that,
1 mile = 1609.34 m
200 m = 0.124 miles
19.8 seconds = 0.0055 h
So,
Speed = distance/time
So, the runner's average speed is 22.54 mph.
Answer:
3.25 seconds
Explanation:
It is given that,
A person throws a baseball from height of 7 feet with an initial vertical velocity of 50 feet per second. The equation for his motion is as follows :
Where
s is the height in feet
For the given condition, the equation becomes:
When it hits the ground, h = 0
i.e.
It is a quadratic equation, we find the value of t,
t = 3.25 seconds and t = -0.134 s
Neglecting negative value
Hence, for 3.25 seconds the baseball is in the air before it hits the ground.
Answer:
2 m/s^2
Explanation:
a = v^2/r
a = (10m/s)^2 / 50m
a = 2 m/s^2
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Leave a like and mark brainliest if this helped
Answer:
Explanation:
Part 0
All the spring moves is 2 cm
x = 2 cm * [1 m / 100 cm ]
x = 0.020 meters
F = k*d
100N = k * 0.02 m
100 N / 0.02 = k
5000 N / m
Part A
The spring feels a force of 100 N - - 100N = 200 N because each person is pulling in the opposite direction.
F = k * x
200N = 5000 N/m * d
200 / 5000 = d
d = 0.04 meters.
Part B
10.2 kg must be converted to a force as experienced here on earth.
F = m * g
g = 9.81
m = 10.2
F = 10.2 * 9.81
F = 100.06 N
F = k * d
100.06 = 5000 * d
d = 100.06 / 5000
d = 0.02 meters.