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zmey [24]
3 years ago
10

Hi

Physics
2 answers:
vaieri [72.5K]3 years ago
5 0
<h2><u>Explanation:</u></h2>

<em>m = h₂/h₁</em>

Here,

  • <em>m</em> = Magnification
  • <em>h₁ </em>= Height of the object
  • <em>h₂</em> = Height of the image formed by the concave mirror

Magnification given is (-3). The linear magnification here is negative.

This implies that <em>h₂ < h₁</em> because <em>m < 1</em>.

Therefore, the image formed is <u>real and inverted</u>. It is <u>smaller than the object</u>. So, the image is formed between the Centre of Curvature & the Focus.

<em>[NOTE: If the image is highly reduced, it is formed at the focus.]</em>

romanna [79]3 years ago
3 0

Answer:HERE IS YOUR ANSWER

THE POINTS ARE

IF WE PUT THE OBJECT BETWEEN THE FOCUS

AND THE POLE

THEN THE IMAGE FORMED WILL be MAGNIFIED

If that’s not what you are looking for, try this one:

For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.  

Given here the "size of the image" is twice to that of the object.

Hence, it is consider that the magnification is +2.

So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."

Explanation:

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9. A wave on Beaver Dam Lake passes by two docks that are 40.0 m apart.
Kobotan [32]

Answers:

a) 10 m

b) time=1.6 s, frquency=0.625 Hz

c) 6.25 m/s

Explanation:

a) If there is a crest at each dock and another three crests between the two docks, and the wavelength \lambda is the distance between to crests; this means we have 4\lambda in 40 m:

40 m=4\lambda

Clearing \lambda:

\lambda=\frac{40 m}{4}

\lambda=10 m

b) This part can be solved by a Rule of Three:

If 10 waves ---- 16 s

1 wave ----- T

Then:

T=\frac{(1 wave)(16 s)}{10 waves}

T=1.6 s This is the period of the wave

On the other hand, the frequency f of the wave has an inverse relation with its period T:

f=\frac{1}{T}

f=\frac{1}{1.6 s}

f=0.625 Hz This is the frequency of the wave

c) The speed v of a wave is given by the following equation:

v=\frac{\lambda}{T}

v=\frac{10 m}{1.6 s}

Finally:

v=6.25 m/s

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