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zmey [24]
3 years ago
10

Hi

Physics
2 answers:
vaieri [72.5K]3 years ago
5 0
<h2><u>Explanation:</u></h2>

<em>m = h₂/h₁</em>

Here,

  • <em>m</em> = Magnification
  • <em>h₁ </em>= Height of the object
  • <em>h₂</em> = Height of the image formed by the concave mirror

Magnification given is (-3). The linear magnification here is negative.

This implies that <em>h₂ < h₁</em> because <em>m < 1</em>.

Therefore, the image formed is <u>real and inverted</u>. It is <u>smaller than the object</u>. So, the image is formed between the Centre of Curvature & the Focus.

<em>[NOTE: If the image is highly reduced, it is formed at the focus.]</em>

romanna [79]3 years ago
3 0

Answer:HERE IS YOUR ANSWER

THE POINTS ARE

IF WE PUT THE OBJECT BETWEEN THE FOCUS

AND THE POLE

THEN THE IMAGE FORMED WILL be MAGNIFIED

If that’s not what you are looking for, try this one:

For concave mirror the virtual image is formed when the object is kept in between the pole and the focus.  

Given here the "size of the image" is twice to that of the object.

Hence, it is consider that the magnification is +2.

So, the magnification value is positive and the image formed will be "virtual and erect". Thus, the object should be kept in between the "pole and the focus" in concave mirror."

Explanation:

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A mass free to vibrate on a level, frictionless surface at the end of a horizontal spring is pulled 35 cm from its equilibrium p
saul85 [17]

Answer:

0.67 s

Explanation:

This is a simple harmonic motion (SHM).

The displacement, x, of an SHM is given by

x = A\cos(\omega t)

A is the amplitude and \omega is the angular frequency.

We could use a sine function, in which case we will include a phase angle, to indicate that the oscillation began from a non-equilibrium point. We are using the cosine function for this particular case because the oscillation began from an extreme end, which is one-quarter of a single oscillation, when measured from the equilibrium point. One-quarter of an oscillation corresponds to a phase angle of 90° or \frac{\pi}{4} radian.

From trigonometry, \sin A =\cos B if A and B are complementary.

At t = 0, x = 3.5

3.5 = A\cos(\omega \times0)

A =3.5

So

x = 3.5\cos(\omega t)

At t = 0.12, x = 1.5

1.5 = 3.5\cos(0.12\omega)

\cos(0.12\omega)=\dfrac{1.5}{3.5}=0.4286

0.12\omega =\cos^{-1}0.4286

0.12\omega = 1.13

\omega = 9.4

The period, T, is related to \omega by

T = \dfrac{2\pi}{\omega} = \dfrac{2\times3.14}{9.4}=0.67

5 0
3 years ago
To raise an arm upward, the muscle on one side of it contracts. What happens to the muscle on the opposite side of the arm?
enyata [817]

Answer:

It relaxes

Explanation:

I took the test I hope it helps

5 0
3 years ago
Read 2 more answers
Wind resistance _____ as speed increases.
Rudik [331]

The correct option is option B that wind resistance increases dramatically.

Explanation:

When the speed of an object increases resistance increases drastically because the object pushing through air has obtained a high speed but the air is unable to move out of the way so fast so show it tends to get compressed and oppose the moving object and the object names to put more pressure because some of the pressure goes into cutting air and moving through it.

7 0
3 years ago
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A parallel beam of light of wavelength 4.5 x 10^-7 m is incident on a pair of slits that are 5.0 x 10^-4 m apart. The interferen
RSB [31]

Answer:

1.8x10⁻³m

Explanation:

From the question above, the following information was used to solve the problem.

wavelength λ = 4.5x10⁻⁷m

Length L = 2.0 meters

distance d = 5 x 10₋⁴m

ΔY = λL/d

= 4.5x10⁻⁷m (2) / 5 x 10₋⁴m

= 0.00000045 / 0.0005

= 0.0000009/0.0005

= 0.0018

= 1.8x10⁻³m

from the solution above The separation between two adjacent bright fringes is most nearly 1.8x10⁻³m

thank you!

3 0
3 years ago
Which units are used to measure both velocity and speed?
irina1246 [14]
The SI unit for velocity and speed is meters per second
4 0
3 years ago
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