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andriy [413]
3 years ago
14

For general projectile motion, when the projectile is at the highest point of its trajectory, its acceleration is zero? A)The ho

rizontal and vertical components of its velocity are zero. B) Its velocity is perpendicular to the acceleration. C)The horizontal component of its velocity is zero. D)Its velocity and acceleration are both zero.
Physics
1 answer:
Daniel [21]3 years ago
4 0

Answer:

B) Its velocity is perpendicular to the acceleration.

Explanation:

For general projectile motion, the horizontal acceleration is 0 and the vertical acceleration is -g.  This is true for all points on the trajectory.

At the highest point, the vertical velocity is 0.  So you have only a horizontal velocity as well as a vertical acceleration.  So the two are perpendicular.

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A solar eclipse that occurs when the new moon is too far from Earth to completely cover the Sun can be either a partial solar ec
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4 years ago
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3 years ago
You are driving your motorcycle in a circle of radius 75 m on wet pavement. what is the fastest you can go before you lose tract
stira [4]

On driving your motorcycle in a circle of radius 75 m on wet pavement, the fastest you can go before you lose traction, assuming the coefficient of static friction is 0.20 is 147m/s

Friction helps to maintain the slipping of the vehicle on the road hence lays a very important role.

Maximum velocity of a road with friction is given by the formula,

v = μRg

where, v is the maximum velocity

μ is the coefficient of static friction

R is the radius of the circle road

g is the acceleration due to gravity

Given,

μ = 0.20

R = 75m

g = 9.8m/s²

On substituting the given values in the above formula,

v = 0.20× 75 ×9.8

v = 147m/s

So, the Maximum velocity of the wet road is 147m/s.

Learn more about Velocity here, brainly.com/question/18084516

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2 years ago
A stone is thrown horizontally at a speed of 10.0 m/s from the top of a cliff 139.4 m high.
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Answer:

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Explanation:

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