Answer:
1.50 × 10²⁴ atoms C
Explanation:
Step 1: Define
Molar mass of C - 12.01 g/mol
Avagadro's Number: 6.02 × 10²³ atoms, molecules, formula units, etc.
Step 2: Use Dimensional Analysis
= 1.50375 × 10²⁴ atoms C
Step 3: Simplify
We are given 3 sig figs.
1.50375 × 10²⁴ atoms C ≈ 1.50 × 10²⁴ atoms C
Answer:
Check the explanation
Explanation:
As we know the reaction of EDTA and
+ and EDTA and
+
Let us say that the ratio is 1:1
Therefore, the number of moles of
+ = molarity * volume
= 0.0400M * 0.011L
= 0.00044 moles
Therefore excess EDTA moles = 0.00044 moles
Given , initial moles of EDTA = 0.0430 M * 0.025 L
= 0.001075
Therefore reacting moles of EDTA with
= 0.001075 - 0.00044 = 0.000675 moles
Let us say that the ratio between
and EDTA is 1:1
Therefore moles of
= 0.000675 moles
Molarity = moles / volume
= 0.000675 moles / 0.057 L
= 0.011 M (answer).
Because anymore water will breakdown the bonds of your Oh groups
Answer:

Explanation:
We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 28.01 17.03
N₂ + 3H₂ ⟶ 2NH₃
m/g: 240.0
(a) Moles of NH₃

(b) Moles of N₂

(c) Mass of N₂

Answer:
Explanation:
Given that:
the temperature
= 250 °C= ( 250+ 273.15 ) K = 523.15 K
Pressure = 1800 kPa
a)
The truncated viral equation is expressed as:

where; B = -
C = -5800 
R = 8.314 × 10³ cm³ kPa. K⁻¹.mol⁻¹
Plugging all our values; we have


Multiplying through with V² ; we have


V = 2250.06 cm³ mol⁻¹
Z = 
Z = 
Z = 0.931
b) The truncated virial equation [Eq. (3.36)], with a value of B from the generalized Pitzer correlation [Eqs. (3.58)–(3.62)].
The generalized Pitzer correlation is :












The compressibility is calculated as:


Z = 0.9386


V = 2268.01 cm³ mol⁻¹
c) From the steam tables (App. E).
At 
V = 0.1249 m³/ kg
M (molecular weight) = 18.015 gm/mol
V = 0.1249 × 10³ × 18.015
V = 2250.07 cm³/mol⁻¹
R = 729.77 J/kg.K
Z = 
Z = 
Z = 0.588