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Gre4nikov [31]
3 years ago
10

What is the criteria to place an element in a particular group?

Chemistry
1 answer:
emmainna [20.7K]3 years ago
4 0

Answer: The criteria to place elements into groups and periods lies in their atomic number

Explanation:

As we know that period is the horizontal rows of elements in the periodic table and groups are vertical column of elements in the periodic table.

In a period we place those elements that have same number of shells and in a group those elements are placed that have different number of shells and the number of shells increases from top to bottom in a periodic table

For example

Sodium having symbol Na, atomic number of sodium is eleven it's electronic configuration is 1s2,2s2,2p6,3s1, next to it in a period is places potassium having symbol,K, it's electronic configuration is 1s2,2s2,2p6,3s2.

Sodium and potassium both r placed in a period not in a group because both of these have same outer most shell, only the number of electron in outer most shell varies.

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I think this is it.

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As all the mass of other molecules are given and we have to find the mass of hydrogen so total subtracted by carbon and oxygen.

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What carries electric current from the cell to the other components of a circuit.​
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The different objects that make up a circuit are called components. A circuit must have a power source, such as a battery, and the current flows through a conductor, such as a wire.

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I hope that was useful.

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You decide to clean the bathroom. You notice that the shower is covered in a strange green slime. You try
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2 years ago
1. A solution is always a mixture (true or false)
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Answer:

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4 0
3 years ago
NH4NO3, whose heat of solution is 25.7 kJ/mol, is one substance that can be used in cold pack. If the goal is to decrease the te
makvit [3.9K]

Answer:

There are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

Explanation:

To decrease the temperature of the solution there are necessaries:

4,184J/g°C×(5,0°C-25,0°C)×(100,0g+X) = -Y

8368J + 83,68J/gX = Y <em>(1)</em>

Where x are grams of NH₄NO₃ you need to add and Y is the energy that you need to decrease the heat.

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Y = 25700J/mol×\frac{1mol}{80,043g}X

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Replacing (2) in (1)

8368J + 83,68J/g X = 321J/g X

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<em>X = 35,2g</em>

<em />

Thus, there are necessaries 35,2g of NH₄NO₃ per 100,0g of water to decrease the temperature of the solution from 25,0°C to 5,0°C

I hope it helps!

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3 years ago
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