1. Determinati masa moleculara, raportul atomic si raportul de masa pentru oxidul de aluminiu 2. Determinati compozutia procebtu
1 answer:
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Answer:
A)
<u>4, 7, 4, 6</u>
B)
<u>12 moles</u>
Explanation:
__↑______↑
8.00 mol | 14.00 mol
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You can turn this into a system of variables which are solvable.
To do this, create variables for the coefficients of each compound in the reaction respectively.
Because to be balanced, the count of atoms in each element of the compound correspond to the coefficient of the variable in that compound so that the count of the left (reactant) side is set equal to the right (product) side.
a corresponds to the coefficient of the first compound, b corresponds to the coefficient of the second compound, c corresponds to the coefficient of the third compound, and d corresponds to the coefficient of the fourth compound.
(Reactant = Product)
Reactant: 1a [N] Product: 1c.
Reactant: 3a [H] Product: 2d.
Reactant: 2b [O] Product: 2c + 1d.
Thus the system is:
1a = 1c
3a = 2d
2b = 2c + 1d.
Then just use the substitution methods to solve.
Answer:
The weight of the Astroturf is 179,684.31 Newtons.
Explanation:
Length of a soccer field = 0.06214 mile = 328.0992 feet
(1 mile = 5280 feet)
Breadth of a soccer field = 253 feet
Length of a Astroturf which soccer field is to be covered, l = 328.0992 feet
Breadth of a Astroturf which soccer field is to be covered ,b = 253 feet
Thickness of a Astroturf with which soccer field is to be covered = h
h = ½ inch = 0.5 inch = 0.041665 feet
(1 inches = 0.08333 feet)
Volume of the Astroturf ,V= l × b × h
Mass of the Astroturf = m
Density of the Astroturf = d = 187
1 oz = 0.0283495 kg
Weight of the Astroturf = W
W = mg
The weight of the Astroturf is 179,684.31 Newtons.