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2 years ago

8

Why does a beta particle have an atomic number of -1

1 answer:

Fudgin [204]2 years ago

6 0

I cant entirely tell for now but an article on rodioactivity should solve the problem

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Post laboratory reflections 1 write equation [2] in the net ionic form 2. describe what happens when strong acid acts on limesto

oee [108]

It deteriorates. Definitely more than when you started.

4 0

2 years ago

What is aluminum’s nuclear charge?

natita [175]

Answer:All six of the ions contain 10 electrons in the 1s, 2s, and 2p orbitals, but the nuclear charge varies from +7 (N) to +13 (Al)

Explanation:

hope this helped if it did may i have brainliest

5 0

3 years ago

Read 2 more answers

A silver ring has a mass of 138.45 g. how many calories of heat are required to increase the temperature from 11.8 c to 162.5 c?

garik1379 [7]

A heat energy of 645

5 0

2 years ago

Read 2 more answers

After balancing the following reaction under acidic conditions, how many mole equivalents of water are required and on which sid

nordsb [41]

Answer:

d. 8 moles of H2O on the product side

Explanation:

Hello,

In this case, we need to balance the given redox reaction in acidic media as shown below:

$MnO_4^{1-} (aq) + Cl^{1-} (aq) \rightarrow Mn^{2+} (aq) + Cl_2 (g)\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq) + Cl^{1-} (aq) \rightarrow Mn^{2+} (aq) + Cl_2 (g)\\\\\\\\(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O\\\\2Cl^{1-}\rightarrow Cl_2^0+2e^-\\\\2*[(Mn^{7+}O^{2-}_4)^{1-} (aq)+8H^++5e^- \rightarrow Mn^{2+}+4H_2O]\\\\5*[2Cl^{1-}\rightarrow Cl_2^0+2e^-]\\\\\\\\2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10e^- \rightarrow 2Mn^{2+}+8H_2O\\\\10Cl^{1-}\rightarrow 5Cl_2^0+10e^-\\$

Then, we add the half reactions:

$2(Mn^{7+}O^{2-}_4)^{1-} (aq)+16H^++10Cl^{1-} \rightarrow 2Mn^{2+}+8H_2O+5Cl_2^0$

Thereby, we can see d. 8 moles of H2O on the product side.

Best regards.

4 0

2 years ago

What is the electron configuration for La (lanthanum)?

MrRissso [65]

Answer:

Lathanum .

Atomic number = 57

Symbol = La

Atomic weight = 138.9

No of energy orbitals = 6

Electronic configuration

$[Xe]6s^25d^1$

7 0

2 years ago