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lina2011 [118]
2 years ago
7

a liquid that occupies a volume of 5.0L gas a mass of 6.0 kg. what is the density of the liquid in kg/L?

Chemistry
1 answer:
AysviL [449]2 years ago
7 0

Answer:

1.2Kg/l

Explanation:

Density=Mass/Volume

Density=6.0/5.0

Density=1.2Kg/l

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How many moles of water are in 1.23x10^18 water molecules
Harlamova29_29 [7]

By 1.23 x 1024 you mean 10 to the power of 24 molecules? If so all you need to do is divide the number of molecules you have by Avagadros number, 6.022 x 10^23. This will give you the mols of water, or the mols of anything, since there is always 6.022 x 10^23 molecules in 1 mol of substance.


1.23x10^24 atoms/6.022x10^23 atom/mol = 2.04 mol H20


6 0
3 years ago
Read 2 more answers
When a compound such as X2Z4 is created, what would be the<br> correct simplified chemical formula?
Shtirlitz [24]

Answer:

XZ2

Explanation:

There are different ways in which compounds can be represented. Broadly, we have three different types of formula;

- Structural formular: This shows how th atoms in te compound are connected to each other.

- Molecular formular: This shows the actual number of atoms of element present in the compound

- Empirical Formular: This is the simplest formular of a compound. It basically shows the number of atoms in simple ration to each other.

This question requires us to input the empirical formular;

X2Z4

The ratio of the elements is; 2 : 4 which can be simplified into 1 : 2

This means the empirical formular is XZ2

6 0
3 years ago
Which element would make a poor, brittle conductor? use the periodic table for help. a. sulfur b. boron c. cobalt d. calcium?
Greeley [361]
I think the answer is C or B
8 0
3 years ago
7. How many moles are in 5 x 10 2 atoms of gold?
goblinko [34]

Answer:

8.3028894e-22

Explanation:

5x10^2 atoms/1 x 1 mol/6.022x10^23

7 0
3 years ago
In a certain industrial process involving a heterogeneous catalyst, the volume of the catalyst (in the shape of a sphere) is 10.
olga nikolaevna [1]

Answer:

a. The second run will be faster.

d. The second run has twice the surface area.

Explanation:

The rate of a reaction is proportional to the surface area of a catalyst. Given the volume (V) of a sphere, we can find its surface area (A) using the following expression.

A=\pi ^{1/3} (6V)^{2/3}

The area of the 10.0 cm³-sphere is:

A=\pi ^{1/3} (6.10.0)^{2/3}=22.4cm^{2}

The area of each 1.25 cm³-sphere is:

A=\pi ^{1/3} (6. 1.25)^{2/3}=5.61cm^{2}

The total area of the 8 1.25cm³-spheres is 8 × 5.61 cm² = 44.9 cm²

The ratio of  8 1.25cm³-sphere to 10.0 cm³-sphere is 44.9 cm²/22.4 cm² = 2.00

Since the surface area is doubled, the second run will be faster.

6 0
3 years ago
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