The molar concentration of the KI_3 solution is 0.251 mol/L.
<em>Step 1</em>. Write the <em>balanced chemical equation</em>
I_3^(-) + 2S_2O_3^(2-) → 3I^(-) + S_4O_6^(2-)
<em>Step 2</em>. Calculate the <em>moles of S_2O_3^(2-)</em>
Moles of S_2O_3^(2-)
= 27.9 mL S_2O_3^(2-) ×[0.270 mmol S_2O_3^(2-)/(1 mL S_2O_3^(2-)]
= 7.533 mmol S_2O_3^(2-)
<em>Step 3</em>. Calculate the <em>moles of I_3^(-)
</em>
Moles of I_3^(-) = 7.533 mmol S_2O_3^(2-)))) × [1 mmol I_3^(-)/(2 mmol S_2O_3^(2-)] = 3.766 mmol I_3^(-)
<em>Step 4</em>. Calculate the <em>molar concentration of the I_3^(-)
</em>
<em>c</em> = "moles"/"litres" = 3.766 mmol/15.0 mL = 0.251 mol/L
Answer:
I have no idea what you mean.
Explanation:
Answer:
V₂ = 1.41 L
Explanation:
Given data:
Initial temperature = 35°C (35 +273.15 K = 308.15 K)
Initial volume = 1.5 L
Final temperature = 17°C (17+273.15 K = 290.15 K)
Final volume = ?
Solution:
The given problem will be solve through the Charles Law.
According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.
Mathematical expression:
V₁/T₁ = V₂/T₂
V₁ = Initial volume
T₁ = Initial temperature
V₂ = Final volume
T₂ = Final temperature
Now we will put the values in formula.
V₁/T₁ = V₂/T₂
V₂ = V₁T₂/T₁
V₂ = 1.5 L × 290.15 K / 308.15 k
V₂ = 435.23 L.K / 308.15 k
V₂ = 1.41 L
Correct Answer: option B. moderately polar covalent
Reason:
Both phosphorus and oxygen are non-metals, and hence they are bonded by covalent bonds. Furthermore, the electro negativity of P and O is 2.1 and 3.5 respectively. The difference in electro negativity is 1.4. Due to the difference in electro negativity, nature of the P-O bond in phosphorus pentoxide (P2O5) is moderately polar covalent.