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Sergio [31]
2 years ago
11

draw and name all monochloro products you would expect to obtain from the radical chlorinatioj of 2 methylpentane. which if any

are chiral:
Chemistry
1 answer:
solong [7]2 years ago
8 0

In total, there are 5 monochloro products obtained from the Free-radical chlorination of 2- methyl pentane.

<h3>What is Free-radical chlorination?</h3>
  • Free-radical chlorination is a form of chlorination in organic chemistry. Alkanes and aromatics with alkyl substitutes frequently undergo this chemical reaction when exposed to UV radiation. Chloroform, dichloromethane, and hexachlorobutadiene are produced industrially using this reaction.
  • A free-radical chain mechanism drives its progression. The various halogens have quite varying levels of reactivity. Fluorine has higher relative rates than chlorine, bromine, and iodine.
  • Alkane reactions with fluorine are therefore difficult to manage, those with chlorine are moderate to fast, those with bromine are slow and necessitate high UV exposure levels, and those with iodine are almost nonexistent and thermodynamically unfavorable.
  • The Wohl-Ziegler reaction, an approach frequently used in chemical synthesis and involving N-bromosuccinimide,

To learn more about radical chlorination with the given link

brainly.com/question/2272447

#SPJ4

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The pH of the buffer is 6.1236.

Explanation:

The strength of any acid solution can be obtained by determining their pH. Even the buffer solution strength of the weak acid can be determined using pH. As the dissociation constant is given, we can determine the pKa value as the negative log of dissociation constant value.

pKa=-log[H] = - log [ 5.66 * 10^{-7}]\\ \\pka = 7 - log (5.66)=7-0.753=6.247\\\\pka = 6.247

The pH of the buffer can be known as

pH = pK_{a} + log[\frac{[A-]}{[HA]}}]

The concentration of [A^{-}] = Moles of [A]/Total volume = 0.608/2 = 0.304 M\\

Similarly, the concentration of [HA] = \frac{Moles of HA}{Total volume} = \frac{0.809}{2} = 0.404

Then the pH of the buffer will be

pH = 6.247 + log [ 0.304/0.404]

pH = 6.247 + log 0.304 - log 0.404=6.247-0.517+0.3936=6.1236

So, the pH of the buffer is 6.1236.

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The kinetic-molecular theory as it applies to gases has five basic assumptions.

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Explanation:

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